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3 years ago

The angle of reflection is the angle the _____ to the reflecting surface.

Physics

2 answers:

worty [1.4K]3 years ago

8 0

Answer:

3. reflected ray makes with a perpendicular line

Explanation:

- The angle of incidence is defined as the angle between the incident ray and the perpendicular to the surface

- The angle of reflection is defined as the angle between the reflected ray and the perpendicular to the surface

According to this second definition, we see that the correct answer that completes the sentence is (3):

The angle of reflection is the angle the 3. reflected ray makes with a perpendicular line to the reflecting surface.

The law of reflection also states that the angle of reflection is equal to the angle of incidence.

Licemer1 [7]3 years ago

5 0

Answer:

reflected ray makes with a perpendicular line

Explanation:

its on my test

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3 years ago

A drone flies 8 m/s due East with respects to the wind. The wind is blowing 6 m/s due North with respects to the ground. What is

vekshin1

Answer:

B. 10m/s

Explanation:

If a drone flies 8 m/s due East with respects to the wind and the wind is blowing 6 m/s due North, the speed of the drone with respect to the ground is its displacement.

Displacement is calculated using Pythagoras theorem.

d² = 8²+6²

d² = 64+36

d² = 100

Square root both sides

√d² = √100

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Hence the distance of the drone with respect to the ground is 10m/s

Option B is correct

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3 years ago

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sergey [27]

Answer:

Explanation:

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2 years ago

The mass of a radioactive substance follows a continuous exponential decay model, with a decay rate parameter of 1% per day. A s

Bumek [7]

Answer:

2,38kg

Explanation:

Mass in function of time can be found by the formula: $m_{(t)} =m_{0} e^{-kt}$ , where $m_{0}$ is the initial mass, t is the time and k is a constant.

Given that a sample decay 1% per day, that means that after first day you have 99% of mass.

$m_{(1)} =m_{0} e^{-k(1)}$ , but $m_{(1)}=\frac{99m_{0} }{100}$ , so we have $\frac{99m_{0} }{100}=m_{0}e^{-k}$ , then $k=-ln(\frac{99}{100})=0.01$

Now using k found we must to find $m_{(5)}$ .

$m_{(5)}=m_{0}e^{-(0.01)5}=2.5kge^{-0.05} =2.5x0.951=2.38kg$

6 0

3 years ago