Answer:
24m/s²
Explanation:
Given
Distance S = 3m
Time of fall = 0.5sec
Required
Acceleration due to gravity
Using the equation of motion
S = ut+1/2gt²
Substitute the given values
3 = 0+1/2g(0.5)²
3 = 1/2(0.25)g
3 = 0.125g
g = 3/0.125
g = 24
Hence the value for the acceleration of gravity on this new planet is 24m/s²
Answer:
The magnetic field will be
, '2d' being the distance the wires.
Explanation:
From Biot-Savart's law, the magnetic field (
) at a distance '
' due to a current carrying conductor carrying current '
' is given by
![\large{\overrightarrow{B} = \dfrac{\mu_{0}I}{4 \pi}} \int \dfrac{\overrightarrow{dl} \times \hat{r}}{r^{2}}}](https://tex.z-dn.net/?f=%5Clarge%7B%5Coverrightarrow%7BB%7D%20%3D%20%5Cdfrac%7B%5Cmu_%7B0%7DI%7D%7B4%20%5Cpi%7D%7D%20%5Cint%20%5Cdfrac%7B%5Coverrightarrow%7Bdl%7D%20%5Ctimes%20%5Chat%7Br%7D%7D%7Br%5E%7B2%7D%7D%7D)
where '
' is an elemental length along the direction of the current flow through the conductor.
Using this law, the magnetic field due to straight current carrying conductor having current '
', at a distance '
' is given by
![\large{\overrightarrow{B}} = \dfrac{\mu_{0}I}{2 \pi d}](https://tex.z-dn.net/?f=%5Clarge%7B%5Coverrightarrow%7BB%7D%7D%20%3D%20%5Cdfrac%7B%5Cmu_%7B0%7DI%7D%7B2%20%5Cpi%20d%7D)
According to the figure if '
' be the current carried by the top wire, '
' be the current carried by the bottom wire and '
' be the distance between them, then the direction of the magnetic field at 'P', which is midway between them, will be perpendicular towards the plane of the screen, shown by the
symbol and that due to the bottom wire at 'P' will be perpendicular away from the plane of the screen, shown by
symbol.
Given
and ![\large{I_{B} = 12.5 A}](https://tex.z-dn.net/?f=%5Clarge%7BI_%7BB%7D%20%3D%2012.5%20A%7D)
Therefore, the magnetic field (
) at 'P' due to the top wire
![B_{t} = \dfrac{\mu_{0}I_{t}}{2 \pi d}](https://tex.z-dn.net/?f=B_%7Bt%7D%20%3D%20%5Cdfrac%7B%5Cmu_%7B0%7DI_%7Bt%7D%7D%7B2%20%5Cpi%20d%7D)
and the magnetic field (
) at 'P' due to the bottom wire
![B_{b} = \dfrac{\mu_{0}I_{b}}{2 \pi d}](https://tex.z-dn.net/?f=B_%7Bb%7D%20%3D%20%5Cdfrac%7B%5Cmu_%7B0%7DI_%7Bb%7D%7D%7B2%20%5Cpi%20d%7D)
Therefore taking the value of
the net magnetic field (
) at the midway between the wires will be
![\large{B_{M} = \dfrac{4 \pi \times 10^{-7}}{2 \pi d} (I_{t} - I_{b}) = \dfrac{2 \times 10^{-7}}{d} = \dfrac{41.4 \times 10 ^{-4}}{d}} T](https://tex.z-dn.net/?f=%5Clarge%7BB_%7BM%7D%20%3D%20%5Cdfrac%7B4%20%5Cpi%20%5Ctimes%2010%5E%7B-7%7D%7D%7B2%20%5Cpi%20d%7D%20%28I_%7Bt%7D%20-%20I_%7Bb%7D%29%20%3D%20%5Cdfrac%7B2%20%5Ctimes%2010%5E%7B-7%7D%7D%7Bd%7D%20%3D%20%5Cdfrac%7B41.4%20%5Ctimes%2010%20%5E%7B-4%7D%7D%7Bd%7D%7D%20T)
1)
HCl: hydrogen, chloride
3CO2: carbon, oxygen
2Na2SO4:sodium, sulphur, oxygen.
2)
-HCl: 1 hydrogen atom, 1 chlorine atom
-CO2: 1 carbon atom, 2 oxygen atoms
-Na2SO4: 2 sodium atoms, 1 sulphur atom, 4 oxygen atoms.
3)
-HCl: 2 atoms
-3CO2: 9 atoms
-2Na2SO4: 14 atoms.
Newtons second law says that the acceleration of an object (produced by a net force) is directly proportional to that magnitude of the net force. E.g. F = ma
where F is the net force of an object, m is mass and a is acceleration.
For example, if an object had a large mass, there would have to be more force in order to move it than if it was lighter.
In a linear motion, if you pushed two objects, one slightly larger than the other, with the same force, the acceleration of the smaller object would be bigger than the larger one. So the motion (change in position over time), of the larger object would be seen as lesser than the smaller one (in a situation where both forces are equal).