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Marianna [84]
2 years ago
14

Look at picture below !! please <3

Physics
1 answer:
balu736 [363]2 years ago
8 0

Answer:

C

Explanation:

compound is a substance made from two or more different elements that have been chemically joined

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5. Calculate the acceleration of a 2 kg block across a table if you push with a force of 20 N and the frictional force is 4 N.
frozen [14]

Answer:

Explanation:hey do you go to GOC too?

8 0
3 years ago
What is the magnitude of the resultant vector? Round your answer to the nearest tenth
Harlamova29_29 [7]

Answer:13.9 on edgy I just did it

Explanation:

7 0
3 years ago
When Royce was 10 years old, he had a mass of
coldgirl [10]

Answer:

<em>The gravitational force between Royce and Earth would be doubled at 16 years.</em>

Explanation:

<em>"Newton's law of universal gravitation states that gravitation force between two masses is proportional to the magnitude of their masses and inverse-squared of their distance".</em>

Royce Scenario

At the age of 10 Royce's mass = 30kg

At the age of 16 Royce's mass = 60kg

From Newton's law of universal gravitation, an Increase in the mass of a body would amount to a corresponding increase in the gravitational force.

In the case of Royce, the mass double between the age of 10 and 16, so there would be an increase of the gravitation force by double.

6 0
3 years ago
How to add an answer
netineya [11]
You cannot add an answer if two people are already answering!
7 0
4 years ago
A 60-kg skate boarder is standing on his stationary board. A bigger, out of control 75-kg skate boarder crashes into him with a
andrezito [222]

Answer:

2.22m/s

Explanation:

Given parameters:

M1  = 60kg

M2  = 75kg

V1  = 0m/s

V2  = 4m/s

Unknown;

Velocity after collision  = ?

Solution:

To solve this problem, we must understand that the momentum before and after collision of the bodies must be the same;

     M1 V1  + M2 V2  = v(M1 + M2)

So;

       60 x 0  +  75 x 4  = v (60 +75)

                 300  = 135v

                   v = 2.22m/s

3 0
3 years ago
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