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olga nikolaevna [1]

4 years ago

6

If the forces acting on an object are balanced, the object may change speed, change direction, or do both. Please select the bes

t answer from the choices provided T F

2 answers:

Leviafan [203]4 years ago

8 0

False is ur answer sorry if i am too late

Eddi Din [679]4 years ago

4 0

Answer: False

Explanation:

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7 0

3 years ago

I will mark brainliest if your answer is correct!

pochemuha

The electromotive force (∈) = 2 V

<h3>Further explanation</h3>

Given

I=2 A

t = 30 s

E = 120 J

Required

The electromotive force (∈)

Solution

The electromotive force : the potential difference between two electrodes in galvanic cell

Can be formulated :

$\tt \epsilon=\dfrac{E}{Q}$

E = energy, J

Q = charge , Coulomb = i.t

$\tt \epsilon=\dfrac{120~J}{2~A\times 30~s}\\\\\epsilon=2~V$

3 0

3 years ago

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Aleks [24]

The answer is step by step 65

4 0

3 years ago

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Two students are on a seesaw. Student B is bigger than student A, so the seesaw is not balanced. How could the seesaw be bounced

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With another person on student A’s side. I’m sorry if I wasn’t able to help. Im trying my best from the information given. :)

3 0

2 years ago

"Two electrons in an atom are separated by 1.4 × 10−10 m, the typical size of an atom. What is the force between them? The Coulo

Rudiy27

Answer:

$F\approx 1.17551\times 10^{-8} N$

Explanation:

In order to find the force between the two electrons, we need to use Coulomb's law. In its scalar form, the law is given by:

$F=k_c \frac{q_1*q_2}{r^2}$

Where:

$k_c=Coulomb\hspace{3}constant\approx 9\times10^{9} \frac{Nm^2}{C^2} \\q_1\hspace{3}and\hspace{3}q_2=Magnitudes\hspace{3}of\hspace{3}the\hspace{3}charges\\r=Distance\hspace{3}between\hspace{3}the\hspace{3}charges$

The electric charge of an electron is a known constant given by:

$q_e \approx -1.6 \times 10^{-19} C$

So:

$q_1=q_2=q_e \approx -1.6 \times 10^{-19} C$

Therefore, replacing the data provided in the Coulomb's law equation:

$F=(9\times 10^{9})\frac{(-1.6\times 10^{-19})*(-1.6\times 10^{-19})}{(1.4\times 10^{-10})^2} =1.175510204\times10^{-8} \approx 1.17551\times10^{-8}N$

8 0

3 years ago