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Yuliya22 [10]
1 year ago
12

Please help meee I will mark brainliless! thank you!!!!!!!!!!!!!

Mathematics
2 answers:
Verizon [17]1 year ago
6 0
23: 1/8
24: 1/4
25: 16/40
26: 12/40
seraphim [82]1 year ago
3 0
0.8 hope this helps!
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Find the value of the variable(s) in each figure. Explain your reasoning. Thank you in advance
inn [45]

Answer:

1. x 55

2. y 117

x 51

3.x39

y116

4.x 18

5.x 48

y 14

for the last one I'm not sure. please give 5 start

4 0
3 years ago
(3x^2+2x-3)(x-1)<br> please help
cupoosta [38]

Answer:

Step-by-step explanation:

(3x^2 + 2x - 3)(x-1)

Expanding the brackets

x(3x^2 +2x - 3) -1(3x^2 +2x -3)

3x^3 +2x^2 -3x -3x^2 -2x + 3

3x^3 - x^2 - 5x + 3

5 0
3 years ago
HURRY PLEASE I BARELY HAVE ANY TIME<br>what is the solution to the system of equations?​
DanielleElmas [232]

Answer:

maybe 3...............................

7 0
3 years ago
A certain project can be completed by 28 men in 90 days. the numbers of men needed varies inversely to the time needed to comple
leva [86]

ANSWER

C. 35 men

EXPLANATION

Let m represent the number of men needed and d represent the number of days.

From the question,the number of men needed varies inversely to the time needed to complete the project.

We can write the inverse variation equation.

m =  \frac{k}{d}

where k is the constant of variation.

When m=28, d =90.

We substitute these values into the variation equation to determine the value of k.

28 =  \frac{k}{90}

k = 90 \times 28

k = 252

Now the equation becomes:

m= \frac{2520}{d}

When d=72,

m =  \frac{2520}{72}

m = 35

Therefore he needs to have 35 men working.

3 0
3 years ago
A circular cylindrical container, open at the top, and having a capacity of 24pi cubic inches, is to be manufactured. If the cos
otez555 [7]

Answer: radius r = 2 inches

height h = 6 inches

Step-by-step explanation:

Given;

Volume V = 24πin3

Volume of a cylinder is given by

V = πr^2h

h = V/πr^2. ....1

Where, h = height and r = radius of cylinder

For the surface area of the cylinder with open top. we have,

S = 2πrh + πr^2

For the cost of materials used, let k represent the cost of materials used for the body of the cylinder.

Then, for the bottom will be 3k

Total cost will be represented by C, which gives

C = 2πrhk + 3πr^2k. .....2

Substituting eqn 1 to 2, we have;

C = 2πrVk/πr^2 + 3πr^2k

C = 2Vk/r + 3πr^2k

The material cost is minimum at dC/dr = 0

dC/dr = -2Vk/r^2 + 6πrk =0

6πrk = 2Vk/r^2

r^3 = 2V/6π

r = (2×24π/6π)^-3

r = (8)^-3

r = 2

Substituting r = 2 into eqn1

h = 24π/π(2^2)

h = 24/4 = 6

h = 6

5 0
3 years ago
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