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2 years ago

What is gravitational energy ?

Physics

1 answer:

Tanzania [10]2 years ago

4 0

The energy of one massive object has in relation with another massive object due to gravity is called gravity

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Two molecules of lithium are combined with 225 grams of bromine to form two molecules of lithium bromide. If you end up with 690

4vir4ik [10]

The amount of Li present to start the reaction is 55.18g

Explanation:

2Li + Br₂ → 2LiBr

Molecular weight of Br₂ = 159.808 g/mol

Mass of Br₂ present = 225 g

Moles of Br₂ present during the reaction = 225 / 159.808

m = 1.4

Molecular weight of LiBr = 86.845 g/mol

Mass of LiBr formed = 690 g

moles of LiBr produced = 690 / 86.845

m(LiBr) = 7.95

According to the balanced equation, 2 molecules of Li reacts to for 2 molecule of LiBr

So, 7.95 moles of LiBr would require 7.95 moles of Li

The molecular weight of Li is 6.941 g/mol

Thus, the amount of lithium present to start the reaction is

$moles = \frac{given weight}{molecular weight} \\\\7.95 = \frac{w}{6.941} \\\\w = 55.18g$

Therefore, the amount of Li present to start the reaction is 55.18g

6 0

3 years ago

Consider an aircraft powered by a turbojet engine that has a pressure ratio of 12. The aircraft is stationary on the ground, hel

agasfer [191]

hocico vlgcogfv ljfouclh la hospice

3 0

3 years ago

A rod of 2.0-m length and a square (2.0 mm X 2.0 mm) cross section is made of a material with a resistivity of 6.0 E–8 Ohm meter

Alex Ar [27]

Answer:

8.33*10^-16 Watt

Explanation:

Given that

Length of the rod, l = 2 m,

Area of the rod, A = 2 x 2 mm² = 4*10^-6 m²

resistivity of the rod, p = 6*10^-8 ohm metre,

Potential difference of the rod, V = 0.5 V

Let R be the resistance of the rod, then

R = p * l / A

R = (6*10^-8 * 2) / (4*10^-6)

R = 3*10^14 ohm

Heat generated per second = V² / R Heat = (0.5)² / (3*10^14)

Heat = 0.25 / 3*10^14

Heat = 8.33*10^-16 Watt

Therefore, the rate at which heat is generated is 8.33*10^-16 Watt

4 0

4 years ago

A 1kg box is pushed on a flat surface that is 250m long. The box is initially at rest and then pushed with a constant Net force

sasho [114]

Answer:

C) 50 m/s

Explanation:

With the given information we can calculate the acceleration using the force and mass of the box.

Newton's 2nd Law: F = ma

5 N = 1 kg * a
a = 5 m/s²

List out known variables:

v₀ = 0 m/s
a = 5 m/s²
v = ?
Δx = 250 m

Looking at the constant acceleration kinematic equations, we see that this one contains all four variables:

v² = v₀² + 2aΔx

Substitute known values into the equation and solve for v.

v² = (0)² + 2(5)(250)
v² = 2500
v = 50 m/s

The final velocity of the box is C) 50 m/s.

7 0

3 years ago

A ray of light passes symmetrically through on equilateral prism of refractive index 1.5. determine

Darina [25.2K]

Answer:

$Angle \: at \: which \: minimum \: deviation \: occur = 37.18\degree$

Explanation:

Given:

Refractive index of prism μ = 1.5

Since the prism is equilateral,

Angle of prism A= 60°

To find:

Angel of incidence for which minimum deviation can occur(δm) ?

Solution:

We know that,

The refractive index, Angle of prism and angle of minimum deviation are correlated with formula,

 $\mu \: = \frac{sin( \frac{A + \delta_m}{2} )}{sin \frac{A}{2} }$ 

Where symbols have their usual meaning.

Substituting the value from given data in formula,

$\mu \: = \frac{sin( \frac{A + \delta_m}{2} )}{sin \frac{A}{2} } \\1.5\: = \frac{sin( \frac{60 + \delta_m}{2} )}{sin \frac{60}{2} } \\ {sin( \frac{60 + \delta_m}{2} )} = 1.5 \times sin30 \\ {sin( \frac{60 + \delta_m}{2} )} = 1.5 \times 0.5 \\ {sin( \frac{60 + \delta_m}{2} )} = 0.75 \\ \frac{60 + \delta_m}{2} = {sin}^{ - 1}(0.75) \\ \frac{60 + \delta_m}{2} = 48.59 \: \degree \\ \delta_m = (48.59 \times 2) - 60\degree \\ \delta_m = (48.59 \times 2) - 60\degree \\ \delta_m = (97.18 - 60)\degree \\ \delta_m = 37.18\degree$

 $Angle \: at \: which \: minimum \: deviation \: occur = 37.18\degree$ 

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4 0

2 years ago