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Alecsey [184]
2 years ago
15

What is the approximate partial pressure of oxygen at 1500 m?

Chemistry
1 answer:
elena55 [62]2 years ago
3 0

The approximate partial pressure of oxygen at 1500 m is 0.18 atm.

<h3>Pressure of the air</h3>

From barometric pressure table;

1500 m = 85 kPa

1 kPa = 0.0099 atm

85 kPa = ?

= 0.84 atm

Oxygen percentage in air  = 21%

<h3>Partial pressure of oxygen in air</h3>

P = 0.21 x P(total)

P = 0.21 x 0.84 atm

P = 0.18 atm

Thus, the approximate partial pressure of oxygen at 1500 m is 0.18 atm.

Learn more about partial pressure here: brainly.com/question/19813237

#SPJ11

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What is the new concentration of a solution of CaSO3 if 10.0 mL of a 2.0 M CaSO3 solution is diluted to 100 ml?
kifflom [539]

Answer: The new concentration of a solution of CaSO_{3} is 0.2 M 10.0 mL of a 2.0 M CaSO_{3} solution is diluted to 100 mL.

Explanation:

Given: V_{1} = 10.0 mL,      M_{1} = 2.0 M

V_{2} = 100 mL,           M_{2} = ?

Formula used to calculate the new concentration is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula as follows.

M_{1}V_{1} = M_{2}V_{2}\\10.0 mL \times 2.0 M = M_{2} \times 100 mL\\M_{2} = 0.2 M

Thus, we can conclude that the new concentration of a solution of CaSO_{3} is 0.2 M 10.0 mL of a 2.0 M CaSO_{3} solution is diluted to 100 mL.

5 0
2 years ago
Anyone want to talk ??​
3241004551 [841]
No is the answer your welcome well I don’t.
7 0
2 years ago
In the lab there is a vile of mercury and it has a mass of 43.0 grams. If the density of mercury is 13.6 g/mL, what is the volum
Vitek1552 [10]

Answer:

<h2>The answer is 3.16 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}

From the question

mass = 43 g

density = 13.6 g/mL

The volume is

volume =  \frac{43}{13.6}  \\   = 3.161764

We have the final answer as

<h3>3.16 mL</h3>

Hope this helps you

8 0
3 years ago
What is the net ionic equation for the reaction that occurs when aqueous copper(II) sulfate is added to excess 6-molar ammonia?a
Karolina [17]

Answer:

c. 2NH₃ + 2H₂O  + Cu²⁺ → Cu(OH)₂(s) + 2NH₄⁺

Explanation:

A net ionic equation is a chemical equation that list only the species that are involved in the reaction.

The reaction of ammonia with copper(II) sulfate CuSO₄ in water is:

2NH₃ + 2H₂O  + CuSO₄ → Cu(OH)₂(s) + 2NH₄⁺ + SO₄²⁻

In an ionic equation, salts are written as ions, that means CuSO₄ must be written as Cu²⁺ + SO₄²⁻. That is:

2NH₃ + 2H₂O  + Cu²⁺ +<u> SO₄²⁻</u> → Cu(OH)₂(s) + 2NH₄⁺ + <u>SO₄²⁻</u>

As in a net ionic equation you must list only the species involved in the reaction (The underlined species don't react), the net ionic equation is:

<em>c</em>. <em>2NH₃ + 2H₂O  + Cu²⁺ → Cu(OH)₂(s) + 2NH₄⁺</em>

<em></em>

I hope it helps!

7 0
3 years ago
Chemistry balance equations C2H +O2=CO2+H2O​
son4ous [18]

Invalid equation.

..............

7 0
2 years ago
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