Answer:
There are several things you can do at home to help reduce your impact on the environment
.
Eat less beef and pork. ...
Think about packaging before you buy products. ...
Turn off lights and other electrical devices when you don't need them. ...
Do not waste water.
Recycle.
Answer:
The net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide is -470.4 kJ/mol.
Explanation:
Step 1 : Calcium carbide and water react to form acetylene and calcium hydroxide

..[1]
Step 2 : Acetylene, carbon dioxide and water react to form acrylic acid
..[2]
Using Hess's law:
[1] × 6 + [2]



The energy released on formation of 5 moles of acrylic acid = -2352 kJ
The energy released on formation of 1 moles of acrylic acid :

Hence, the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide is -470.4 kJ/mol.
KOH + HBr ---> KBr + H2O
0,3 moles of HBr ---in-------1000ml
x moles of HBr-------in------75ml
x = 0,0225 moles of HBr
according to the reaction: 1 mole of KOH = 1 mole of HBr
so
0,0225 moles of HBr = 0,0225 moles of KOH
0,0225 mole of KOH------in-----45ml
x moles of KOH -----------in------1000ml
x = 0,5 moles of KOH
answer: 0,5 mol/dm³ KOH (molarity)
You would be most likely to use a slicing machine if you were using the <u>icebox </u>method to produce cookies.
In the icebox method a type of cookie in which the dough is made, rolled into a stick, and refrigerated until the dough hardens. The dough can be removed from the refrigerator, cut into individual pieces, and then baked. The rest of the dough is returned to the refrigerator until needed.
Icebox method, also known as refrigerator cookies, are sliced and baked cookies. The dough is formed into logs, chilled in the refrigerator (also called an icebox), sliced , and then baked.
Learn more about the Icebox method here,
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According to Boyle's Law, P1V1 = P2V2
where P1 and V1 are initial pressure and volume respectively. P2 and V2 are final pressure and volume receptively.
Given: P2 = 4 P1 and V1 = 10.0l
∴ V2 = 2.5 l
Answer: Final volume of system is 2.5 l