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Svet_ta [14]
3 years ago
8

Nitrogen gas in the atmosphere is converted to forms of nitrogen usable by vegetation via:

Chemistry
1 answer:
lesya692 [45]3 years ago
8 0
<span>FIXATION.In the nitrogen cycle, nitrogen is converted into many chemical forms through biological and physical processes like nitrogen fixation, ammonification, nitrification and denitrification.During ammonification, ammonium ions are released after decomposition of plants.During nitrogen fixation, nitrogen gas is changed to nitrates by nitrogen fixing bacteria in the soil.These are used by vegetation.</span>
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HELpPPPPppp!!!!!! will mark brainless
ANTONII [103]

Answer:

A

Explanation:

This is because in the graph shown line A has a quite greater impact of refraction than line B .

Hence, we can conclude that line A has the greater reaction at a faster rate.

6 0
3 years ago
What type of chemical reaction is NH3
Gekata [30.6K]

Answer:

Combination reaction

Explanation:

N2+H2 = NH3

they combine together to form a product

7 0
4 years ago
Draw the Lewis structure for the compound with the formula COCl2COCl2. Use lines to show bonding electrons.
stira [4]

Answer :  The Lewis-dot structure of COCl_2 is shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, COCl_2

As we know that carbon has '4' valence electrons, chlorine has '7' valence electron and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in COCl_2 = 1(4) + 2(7) + 1(6) = 24

According to Lewis-dot structure, there are 8 number of bonding electrons and 16 number of non-bonding electrons.

6 0
4 years ago
Which of the following reactions have a positive ΔSrxn? Check all that apply.
PolarNik [594]

Answer:

The reactions that have a <em>positive ΔS rxn </em>are the first and the fourth choices:

  • <em>2A(g) + B(s) → 3C(g)</em>

  • <em>2A(g) + 2B(g) → 5C(g)</em>

Explanation:

<em>ΔS rxn </em>is the change of entropy of the chemical reaction.

ΔS rxn = S after reaction - S before reaction.

Therefore, a positive ΔS rxn  means that the entropy after the reaction is greater than the entropy before the reaction.

You may use some assumptions to predict whether a reaction will lead an increase or decrease of the entropy.

First, assume that all the non-shown conditions, such as temperature and pressure, are constant.

Under that assumption, and from the meaning of entropy as a measure of the disorder or randomness of a system you can predict the sign of the change of entropy.

  • <em><u>2A(g) + B(s) → 3C(g)</u></em>

        1)  The solid compounds, B(s) in this case, are very ordered and so they have low entropy.

        2) Gas molecules are highly disordered (scattered), and the greater the number of molecules of the gas the larger the entropy, S).

Hence, since the product side shows 3 gas molecules and the reactant side shows 2 gas molecules and 1 solid molecule, you predict that the products have a larger entropy than the reactants, meaning an increase in entropy: <em>ΔS rxn is positive.</em>

  • <em><u>2A(g) + B(g) → C(g)</u></em>

Using the same reasoning, 3 gas molecules in the  reactant side have more entropy than 1 molecule in the product side, and so the reaction leads to a decrease in the entropy: ΔS rxn is negative

  • <u><em>A(g) + B(g) → C(g)</em></u>

Again, 2 gas molecules in the  reactant side have more entropy than 1 molecule in the product side, and so the reaction leads to a decrease in the entropy: ΔS rxn is negative

  • <u><em>2A(g) + 2B(g) → 5C(g)</em></u>

With the same reasoing, 5 molecules in the product side, lets you predict that will have more entropy than 4 molecules in the reactant side, and, the entropy will increase: <em>ΔS rxn is positive.</em>

6 0
4 years ago
To calculate the frequency of an electromagnetic wave, you need to know the speed of the wave which you already know as 186000 m
nirvana33 [79]
To finish calculating the frequency of an electromagnetic wave, you need the wavelength
3 0
3 years ago
Read 2 more answers
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