Question

(c) A physics teacher sets up a demonstration to teach her Year 10 class ideas about the conservation of momentum. Figure 2 shows a straight, horizontal air track and two air track trolleys, S and T, which can move along it. Figure 2 Sharp pin o Cork S T has a mass of 3 x 10-1 kg and its velocity is 1.4 m/s to the left. S has a mass of 200 g and is stationary. When T collides with S they stick together. Calculate the velocity of the trolleys after the collision. Show your working clearly and give the unit and direction. [5 marks]​

Answer 1

The velocity of the trolleys after the collision will be 0.84 m/sec. Both collide and stick together and move with the same velocity.

What is the law of conservation of momentum?

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

(m₁) is the mass of S=  200 g  =0.2 Kg

(u₁) is the initial velocity of S= 0 m/s

(m₂) is the mass T= 3 x 10⁻¹ kg

(u₂) is the initial velocity of T =  1.4 m/s

(v) is the velocity after collision =.?

According to the law of conservation of momentum;

Momentum before collision =Momentum after collision

$\rm m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\ 3 \times 10^{-1} \times 1.4 + 0.2 \times 0 = v(0.3+0.2) \\\\ 0.5v=0.42 \\\\ v= 0.84 \ m/sec$

Hence, the velocity of the trolleys after the collision will be 0.84 m/sec.

To learn more about the law of conservation of momentum refer;

brainly.com/question/1113396

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