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Nutka1998 [239]
2 years ago
8

If a solution is made by using 0.45 moles of NaCl and dissolving it with water so that the total volume is 0.750 liters, what wi

ll the concentration of that solution be in molarity?
Chemistry
1 answer:
valkas [14]2 years ago
6 0

Answer:

.6 M

Explanation:

.45 moles / .750 liters = .6 M

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Gaseous indium dihydride is formed from the elements at elevated temperature:
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<u>Answer:</u>

<u>For 1:</u> The value of Q_p for above reaction is 36.83

<u>For 2:</u> The value of Q_p for above reaction is 36.83

<u>For 3:</u> The equilibrium partial pressure of Indium is 0.126 atm

<u>For 4:</u> The equilibrium partial pressure of hydrogen gas is 0.094 atm

<u>For 5:</u> The equilibrium partial pressure of Indium dihydrogen is 0.018 atm

<u>Explanation:</u>

We are given:

Partial pressure of Indium gas = 0.0650 atm

Partial pressure of hydrogen gas = 0.0330 atm

Partial pressure of Indium dihydride = 0.0790 atm

The given chemical equation follows:

                      ln(g)+H_2(g)\rightleftharpoons InH_2(g)

<u>Initial:</u>               0.065     0.033           0.079

<u>At eqllm:</u>       0.065-x   0.033-x       0.079+x

  • <u>For 1:</u>

The expression of Q_p for above reaction follows:

Q_p=\frac{p_{InH_2}}{p_{In}\times p_{H_2}}

Putting values in above equation, we get:

Q_p=\frac{0.079}{0.065\times 0.033}=36.83

Hence, the value of Q_p for above reaction is 36.83

  • <u>For 2:</u>

We are given:

K_p of the reaction = 1.48

There are 3 conditions:

  • When K_{p}>Q_p; the reaction is product favored.
  • When K_{p}; the reaction is reactant favored.
  • When K_{p}=Q_p; the reaction is in equilibrium.

As, Q_{p}>K_p for the given reaction, the reaction is reactant favored.

Hence, the reaction proceed in the backward direction to attain equilibrium

  • <u>For 3:</u>

The expression of K_p for above reaction follows:

K_p=\frac{p_{InH_2}}{p_{In}\times p_{H_2}}

Putting values in above equation, we get:

1.48=\frac{(0.079+x)}{(0.065-x)\times (0.033-x)}\\\\x=-0.061,0.835

Neglecting the value of x = 0.835 because the reaction is going backwards. So, by taking this value, the pressure of the reactants will decrease

So, equilibrium partial pressure of Indium = (0.065 - x) = [0.065 - (-0.061)] = 0.126 atm

  • <u>For 4:</u>

The equilibrium partial pressure of hydrogen gas = (0.033 - x) = [0.033 - (-0.061)] = 0.094 atm

  • <u>For 5:</u>

The equilibrium partial pressure of Indium dihydrogen = (0.079 + x) = [0.079 + (-0.061)] = 0.018 atm

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