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Igoryamba
3 years ago
10

Given the information that nitrogen atoms are larger than hydrogen atoms,which of the models best represent ammonia?(NH3)

Chemistry
1 answer:
Ray Of Light [21]3 years ago
4 0

Answer:

<em>The correct option is the structure in the option D. </em>

Explanation:

Ammonia contains a single nitrogen atom bonded to three hydrogen atoms.

The structure present in option A shows a single nitrogen atom bonded with a single hydrogen atom hence it is not correct.

The structure in option B shows a nitrogen atom bonded to four hydrogen atoms hence it is also not correct.

The structure in option C shows a nitrogen atom bonded to two hydrogen atoms hence it is also not correct.

The structure in option D shows a nitrogen atom bonded to three hydrogen atoms which is the correct structure of ammonia (NH3).

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3 years ago
When 7.00 g of hydrogen react with 70.0 g of nitrogen, hydrogen is considered the limiting reactant because:
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7.5 mol of hydrogen would be needed to consume the available nitrogen.

Explanation:

When hydrogen reacts with nitrogen, ammonia is formed as shown below;

3H₂ (g) + N₂ (g) → 2NH₃ (g)

As seen from the equation, every 3 moles of H₂ react with a mole of N₂ to form 2 moles of NH₃.

The limiting factor in a chemical reaction is the reactant that gets depleted first.

Because the molar mass of nitrogen gas is approximately 28g/mol, 70g of nitrogen gas would be 2.5 moles.

The reaction ratio of nitrogen to hydrogen in the reaction is 1 : 3. The reaction would require 2.5 * 3 (7.5) moles of hydrogen for a complete reaction.

However since there are only 7g on hydrogen, (Remember 1 mole of H₂ is approximately 2g), the available moles of H₂ is 7 / 2 = 3.5

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6 0
3 years ago
How much heat is released when 1.4 mol of hydrogen fluoride are produced?
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Answer:

+375.2 KJ.

Explanation:

The balanced equation for the reaction is given below:

H₂ + F₂ —> 2HF ΔH = +536 KJ

From the balanced equation above,

2 moles of HF required +536 KJ .

Finally, we shall determine the heat required to produce 1.4 mol of hydrogen fluoride, HF. This is illustrated below:

From the balanced equation above,

2 moles of HF required +536 KJ .

Therefore, 1.4 moles of HF will require = (1.4 × 536)/2 = +375.2 KJ

Thus, +375.2 KJ of heat energy is required.

7 0
3 years ago
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