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Temka [501]
3 years ago
11

Isn't gelatin just edible slime

Chemistry
2 answers:
weqwewe [10]3 years ago
8 0

Answer:

Huh?

Explanation:

am confused as u lol

tx for free points

Marina86 [1]3 years ago
8 0

Answer:

technically yes.... anyways can you give me brainliest I ONLY NEED ONE MORE

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A 0.568-g sample of fertilizer contained nitrogen as ammonium sulfate, . It was analyzed for nitrogen by heating with sodium hyd
Mariulka [41]

Answer:

6.69%

Explanation:

Given that:

Mass of  the fertilizer = 0.568 g

The mass of HCl used in titration (45.2 mL of 0.192 M)

= 0.192*\frac{45.2}{1000}* \frac{36.5}{1 \ mole}

= 0.313 g HCl

The amount of NaOH used for the titration of excess HCl (42.4 mL of 0.133M)

= \frac{44.3 \ mL * 1.0 \ L}{1000 \ mL} *0.133 \ mole/L

= 0.0058919 mole of NaOH

From the neutralization reaction; number of moles of HCl is equal with the number of moles of NaOH is needed to complete the neutralization process

Thus; amount of HCl neutralized by 0.0058919 mole of NaOH = 0.0058919 × 36.5 g

= 0.2151 g HCl

From above ; the total amount of HCl used = 0.313 g

The total amount that is used for complete neutralization = 0.2151 g

∴ The amount of HCl reacted with NH₃ = (0.313 - 0.2151)g

= 0.0979 g

We all know that 1 mole of NH₃ = 17.0 g , which requires 1 mole of HCl = 36.5 g

Now; the amount of HCl neutralized by 0.0979 HCl = \frac{17}{36.5}*0.0979

= 0.0456 g

Therefore, the mass of nitrogen present in the fertilizer is:

= 0.0456 \ g \ NH_3 * \frac{1  \ mol \ NH_3 }{17.0 \ mol \ of \ NH_3} * \frac{1  \mol \ (NH_4)_2SO_4}{2 \ mol \ NH_3 } * \frac{2 \ mol \ N }{1  \mol \ (NH_4)_2SO_4}* \frac{14.0 g }{1 \ mol \ N}

= 0.038 g

∴ Mass percentage of Nitrogen in the fertilizer = \frac{0.038 \ g}{0.568 \ g} * 100%

= 6.69%

8 0
4 years ago
Read 2 more answers
Calculate the percent oxygen in potassium chlorate (KClO3)
andreev551 [17]

Molar Mass of KCLO3

= 39 + 35.5 + 48 g

= 122.5 g .

So , percentage of Potassium ( K )

= 39 / 122.5 * 100 %

= 31.83 %

Now , percentage of Chlorine ( Cl )

= 35.5 / 122.5 * 100 %

= 28.97 %

So, finally, percentage of Oxygen ( O )

= 48 / 122.5 * 100 %

= 39.18 %

7 0
3 years ago
Read 2 more answers
Ethical Behavior Worksheet Situation 1. You are taking a very difficult chemistry course, which you must pass to maintain your s
krok68 [10]

Answer:

I would not accept it.

Explanation:

Although it is tempting to accept the janitor's offer and save the scholarship, which is not easy to get, I would not accept his offer, as I do not believe in victories based on dishonesty and would be heavy on conscience if I did the opposite. Obviously, I would not like to lose my scholarship and for that reason, I would look for other ways that would be honest and help me improve my grade. If I could not improve and lose the scholarship, I would be extremely sad, but I would be at peace with my conscience.

4 0
3 years ago
Ben observes how quickly some dry wood is burning in a campfire. Which term best relates to Ben’s observation?
Sedbober [7]

Answer:

Reaction rate

Explanation:

We are told that Ben observes how quickly some dry wood is burning in a campfire.

This is an example of reaction rate because it tells us the speed i.e. how fast the dry wood is reacting with the camp fire.

5 0
3 years ago
Write a message to Eric Wu explaining when he can photograph a lunar eclipse and why lunar eclipses happen.
AlekseyPX

A lunar eclipse can be photographed sometimes when Earth is in between the sun and the Moon.

<h3>Why lunar eclipse occur?</h3>

A lunar eclipse occurs when the Sun, Earth, and Moon align in the same line in which the Moon passes into Earth's shadow. In a total lunar eclipse, the entire Moon falls within the darkest part of Earth's shadow, called the umbra so we can conclude that claim 2  is the right answer about lunar eclipse.

Learn more about eclipse here: brainly.com/question/1077760

6 0
2 years ago
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