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xxTIMURxx [149]
3 years ago
9

In an experiment, 2.54 grams of copper completely reacts with sulfur, producing 3.18 grams of copper(I) sulfide.

Chemistry
2 answers:
kozerog [31]3 years ago
5 0

Answer:

               0.64 g of S

Solution:

               The balance chemical equation is as follow,

                                           2 Cu + S ----> Cu₂S

According to equation,

                        127 g (2 mole) Cu produces = 159 g (1 mole) of Cu₂S

So,

                                 2.54 g Cu will produce = X g of Cu₂S

Solving for X,

                     X = (2.54 g * 159 g) / 127 g

                     X = 3.18 g of Cu₂S

Now, it is confirmed that the reaction is 100% ideal. Therefore,

As,

                       127 g (2 mole) Cu required = 32 g (1 mole) of S

So,

                                2.54 g Cu will require = X g of S

Solving for X,

                      X = (2.54 g * 32 g) / 127 g

                      X = 0.64 g of S

____ [38]3 years ago
3 0

Answer : The total mass of sulfur consumed will be, 0.64 grams and the chemical formula of the compound produced is, Cu_2S copper oxide.

Solution :

According to the law of conservation of mass, the total mass of reactant should be equal to the total mass of product.

The balanced chemical reaction will be,

2Cu+S\rightarrow Cu_2S

In this reaction, copper and sulfur are the reactants and copper sulfide is the product.

Let the mass of sulfur be 'x' gram

\text{The total mass of reactants}=\text{Total mass of copper}+\text{Total mass of sulfur}=2.54g+x

\text{The total mass of product}=\text{Total mass of copper sulfide}=3.18g

According to the law of conservation of mass,

\text{The total mass of reactants}=\text{The total mass of product}

2.54g+x=3.18g

x=(3.18-2.54)g

x=0.64g

Therefore, the total mass of sulfur consumed will be, 0.64 grams and the chemical formula of the compound produced is, Cu_2S copper oxide.

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How do i find a ionic formula? <br><br>for example Ca2+ &amp; S2-​
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Step 1

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CaO

Step 2

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Step 1

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A

l

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8 0
3 years ago
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Dovator [93]

Answer:

5 × 10^-4 L

Explanation:

The equation of the reaction is;

2KClO3 = 2KCl + 3O2

Number of moles of KClO3 = 13.5g/122.5 g / mol = 0.11 moles

From the stoichiometry of the reaction;

2 moles of KClO3 yields 3 moles of O2

0.11 moles of KClO3 yields 0.11 × 3/2 = 0.165 moles of oxygen gas

From the ideal gas equation;

PV= nRT

P= 85.4 × 10^4 KPa

V=?

n= 0.165

R= 8.314 J K-1 mol-1

T= 40+273 = 313K

V= 0.165 ×8.134 × 313/85.4 × 10^4

V=429.4/85.4 × 10^4

V= 5 × 10^-4 L

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Answer:

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