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uysha [10]
2 years ago
6

Name the covalent compound: I8P

Chemistry
1 answer:
SOVA2 [1]2 years ago
6 0

There are certain rules to follow when naming covalent compounds. But first, let us look at the definition of Covalent Compounds.

<h3>What are Covalent Compounds?</h3>

When covalent bonds aid the creation of a molecule, in which the atoms have at least one similar pair of valence electrons, a covalent compound is said to have been formed.

A very common example is water (H₂O)

<h3>How are Covalent Compounds named?</h3>

To name a covalent compound, simply list the first element in the formula using the name of the element, then name the second element by adding the suffix "ide" to the stem of the second element's name.

If there is only one atom in the molecule of the first element, then no prefix should be added.

It is to be noted that if the second element in the compound is oxygen, then we should say:

  • monox<em>ide</em> instead of monoox<em>ide</em> and
  • triox<em>ide</em> instead of trox<em>ide</em>, all depending on how many atoms that are involved.

See the attached for the prefixes related to the various number of atoms in the compounds.

It is to be noted that the covalent compound to be named here is not stated hence the general answer.

Learn more about naming covalent compounds at:
brainly.com/question/9841865

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A _____ change occurs when a substance changes phase.<br> physical<br> chemical<br> nuclear
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18.) What is the reading of the liquid in this<br> graduated cylinder
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A buffer with a pH of 4.31 contains 0.31 M of sodium benzoate and 0.24 M of benzoic acid. What is the concentration of [ H 3 O ]
Mnenie [13.5K]

<u>Answer:</u> The hydronium ion concentration in the solution is 1.29\times 10^{-4}M

<u>Explanation:</u>

To calculate the molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Moles hydrochloric acid solution = 0.060 mol

Volume of solution = 1 L

Putting values in above equation, we get:

\text{Molarity of HCl}=\frac{0.060}{1L}\\\\\text{Molarity of HCl}=0.060M

The chemical reaction for aniline and HCl follows the equation:

                   C_6H_5COO^-+HCl\rightarrow C_6H_5COOH+Cl^-

<u>Initial:</u>           0.24          0.060              0.31

<u>Final:</u>             0.18          -                     0.37

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[\text{conjugate acid}]}{[\text{base}]})

pH=pK_a+\log(\frac{[C_6H_5COO^-]}{[C_6H_5COOH]})

We are given:

pK_a = negative logarithm of acid dissociation constant of benzoic acid = 4.2

[C_6H_5COO^-]=0.18M

[C_6H_5COOH]=0.37M

pH = ?

Putting values in equation 1, we get:

pH=4.2+\log(\frac{0.18}{0.37})\\\\pH=3.89

To calculate the hydronium ion concentration in the solution, we use the equation:

pH=-\log[H_3O^+]

pH = 3.89

Putting values in above equation, we get:

3.89=-\log[H_3O^+]

[H_3O^+]=10^{-3.89}=1.29\times 10^{-4}M

Hence, the hydronium ion concentration in the solution is 1.29\times 10^{-4}M

3 0
3 years ago
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