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uysha [10]
1 year ago
6

Name the covalent compound: I8P

Chemistry
1 answer:
SOVA2 [1]1 year ago
6 0

There are certain rules to follow when naming covalent compounds. But first, let us look at the definition of Covalent Compounds.

<h3>What are Covalent Compounds?</h3>

When covalent bonds aid the creation of a molecule, in which the atoms have at least one similar pair of valence electrons, a covalent compound is said to have been formed.

A very common example is water (H₂O)

<h3>How are Covalent Compounds named?</h3>

To name a covalent compound, simply list the first element in the formula using the name of the element, then name the second element by adding the suffix "ide" to the stem of the second element's name.

If there is only one atom in the molecule of the first element, then no prefix should be added.

It is to be noted that if the second element in the compound is oxygen, then we should say:

  • monox<em>ide</em> instead of monoox<em>ide</em> and
  • triox<em>ide</em> instead of trox<em>ide</em>, all depending on how many atoms that are involved.

See the attached for the prefixes related to the various number of atoms in the compounds.

It is to be noted that the covalent compound to be named here is not stated hence the general answer.

Learn more about naming covalent compounds at:
brainly.com/question/9841865

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Determine the mass of CaCO3 required to produce 40.0 mL CO2 at STP. Hint use molar volume of an ideal gas (22.4 L)
cupoosta [38]

Answer:

m_{CaCO_3}=0.179gCaCO_3

Explanation:

Hello,

In this case, since the undergoing chemical reaction is:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

The corresponding moles of carbon dioxide occupying 40.0 mL (0.0400 L) are computed by using the ideal gas equation at 273.15 K and 1.00 atm (STP) as follows:

PV=nRT\\\\n=\frac{PV}{RT}=\frac{1.00 atm*0.0400L}{0.082\frac{atm*L}{mol*K}*273.15 K})=1.79x10^{-3} mol CO_2

Then, since the mole ratio between carbon dioxide and calcium carbonate is 1:1 and the molar mass of the reactant is 100 g/mol, the mass that yields such volume turns out:

m_{CaCO_3}=1.79x10^{-3}molCO_2*\frac{1molCaCO_3}{1molCO_2} *\frac{100g CaCO_3}{1molCaCO_3}\\ \\m_{CaCO_3}=0.179gCaCO_3

Regards.

3 0
3 years ago
You have 100 mL of a solution of benzoic acid in water; the amount of benzoic acid in the solution is estimated to be about 0.30
dimaraw [331]

Answer:

0.00370 g

Explanation:

From the given information:

To determine the amount of acid remaining using the formula:\dfrac{(final \ mass \ of \ solute)_{water}}{(initial \ mass \ of \ solute )_{water}} = (\dfrac{v_2}{v_1+v_2\times k_d})^n

where;

v_1 = volume of organic solvent = 20-mL

n = numbers of extractions = 4

v_2 = actual volume of water = 100-mL

k_d = distribution coefficient = 10

∴

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{100 \ ml}{100 \ ml +20 \ ml \times 10})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{100 \ ml}{100 \ ml +200 \ ml})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{1}{3})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = 0.012345

Thus, the final amount of acid left in the water = 0.012345 * 0.30

= 0.00370 g

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