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krok68 [10]
3 years ago
7

Can someone please help me

Chemistry
1 answer:
Lilit [14]3 years ago
3 0
It is A. Barium

Explanation: I did that already
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Determine the pH of a 5x10^-4 M solution of Ca(OH)2
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Ca(OH)₂ ==> Ca²⁺ + 2 OH<span>-   

Ca(OH)</span>₂ is <span>strong Bases</span><span>

</span>Therefore,  the [OH-] equals 5 x 10⁻⁴ M. For every Ca(OH)₂ you produce 2 OH⁻<span>.
</span>
pOH = - log[ OH⁻]

pOH = - log [ <span>5 x 10⁻⁴ ]

pOH = 3.30

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pH + 3.30 = 14

pH = 14 - 3.30

pH = 10.7

hope this helps!</span>
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Answer:

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