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3 years ago

Determine the compound type for the following formulas

Chemistry

1 answer:

sladkih [1.3K]3 years ago

3 0

C₁₂H₂₂O₁₁ , Mg(OH)₂ , H₂O ,Cu₃Zn₂ , Au are covalent compound,

Ionic Compound ,covalent compound ,metallic compound, metal respectively.

The missing question is

Determine the compound type for the following formulas

C₁₂H₂₂O₁₁ , Mg(OH)₂ , H₂O ,Cu₃Zn₂ , Au

<h3>What are the different types of compound?</h3>

The compounds by the exchange of electrons are called Ionic Compound, Those formed by sharing of electrons is called a covalent compound.

It is given in the question to determine the type of the compounds

1. C₁₂H₂₂O₁₁: It is a covalent compound

2. Mg(OH)₂: It is an Ionic Compound

3. H₂O: It is a covalent compound

4. Cu₃Zn₂: It is a metallic compound

5.Au: It is a metal

To know more about Different types of compound

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<u>Explanation</u>:

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What is the new freezing point for a 0.811m solution of Li2O in water?

rewona [7]

Answer:

Freezing T° of solution = - 4.52°C

Explanation:

ΔT = Kf . m . i

That's the formula for colligative property about freezing point depression.

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Li₂O → 2Li⁺ + O⁻²

3 moles of ions have been formed. Ions dissolved in solution are i, what we call Van't Hoff factor.

m is molality → 0.811 m, this is data

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and ΔT = Freezing T° of pure solvent - Freezing T° of solution

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3 years ago

If the volume of a gas is 958 mL at 75.0 C, at what temperature would the volume of the gas decrease to 822 mL

zhenek [66]

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Assuming pressure is held constant,

$\frac{958}{348}=\frac{822}{T_{2}} \\ \\ \frac{348}{958}=\frac{T_{2}}{822} \\ \\ T_{2}=\frac{(822)(348)}{958} \approx 299 \text{ K} \\ \\ T_{2} \approx 299-273=\boxed{26^{\circ} \text{ C}}$

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