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sergij07 [2.7K]
3 years ago
9

A student massed an unknown sample and found it to be 23.5g. The volume of the sample is 2.00mL. Calculate the density

Chemistry
2 answers:
riadik2000 [5.3K]3 years ago
7 0

Answer:

The density of the sample is 11.8 g/mL.

Explanation:

We are given an unknown sample with a mass of 23.5 g and a volume of 2.00 mL and we want to determine its density.

Recall that density is given by:

\displaystyle \rho = \frac{m}{V}

Where ρ is the density, <em>m</em> is the mass, and <em>V</em> is the volume.

Substitute 23.5 g for <em>m</em> and 2.00 mL for <em>V</em> and evaluate:

\displaystyle \begin{aligned} \rho & = \frac{m}{V} \\ \\ & = \frac{(23.5\text{ g})}{(2.00 \text{ mL})}\\ \\  & = 11.8 \text{ g/mL}\end{aligned}

Hence, the density of the sample is 11.8 g/mL.

wolverine [178]3 years ago
7 0

Answer:

mass=23.5g

volume=2.88ml

Explanation:

But density= mass/volume

23.5/2.88

=8.15kgm^-3

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What amount (moles) of compound is present in 1.00 g of each of the compounds in Exercise 54?
Anika [276]

Answer:

1. Caffeine, C₈H₁₀N₄O₂

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2. Ethanol, C₂H₅OH

Amount = 0.0217 moles

3. Dry Ice, CO₂

amount = 0.0227 moles

<em>Note: The question is incomplete. The compound are as follows:</em>

<em> 1. Caffeine, C₈H₁₀N₄O₂;</em>

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Explanation:

Amount (moles) = mass in grams /molar mass in grams per mole

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molar mass of caffeine = 194 g/mol

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2. Ethanol, C₂H₅OH

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Amount = 1.00 g/46 g/mol = 0.0217 moles

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5 0
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describe how a pure dry sample of solid lead carbonate can be obtained from sodium carbonate solution and lead nitrate solution
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Answer:

Soluble salts can be made by reacting acids with soluble or insoluble reactants. Titration must be used if the reactants are soluble. Insoluble salts are made by precipitation reactions.

Making insoluble salts

An insoluble salt can be prepared by reacting two suitable solutions together to form a precipitate.

Determining suitable solutions

All nitrates and all sodium salts are soluble. This means a given precipitate XY can be produced by mixing together solutions of:

X nitrate

sodium Y

For example, to prepare a precipitate of calcium carbonate:

X = calcium and Y = carbonate

mix calcium nitrate solution and sodium carbonate solution together

calcium nitrate + sodium carbonate → sodium nitrate + calcium carbonate

Ca(NO3)2(aq) + Na2CO3(aq) → 2NaNO3(aq) + CaCO3(s)

It also works if potassium carbonate solution or ammonium carbonate solution is used instead of sodium carbonate solution. Remember that all common potassium and ammonium salts are soluble.

please mark as brainliest

Explanation:

7 0
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