Answer : The specific heat of metal is .
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of metal = ?
= specific heat of water =
= mass of metal = 129.00 g
= mass of water = 45.00 g
= final temperature =
= initial temperature of metal =
= initial temperature of water =
Now put all the given values in the above formula, we get
Therefore, the specific heat of metal is .
Explanation:
The given data is as follows.
Pressure (P) = 760 torr = 1 atm
Volume (V) = = 0.720 L
Temperature (T) = = (25 + 273) K = 298 K
Using ideal gas equation, we will calculate the number of moles as follows.
PV = nRT
Total atoms present (n) =
=
= 0.0294 mol
Let us assume that there are x mol of Ar and y mol of Xe.
Hence, total number of moles will be as follows.
x + y = 0.0294
Also, 40x + 131y = 2.966
x = 0.0097 mol
y = (0.0294 - 0.0097)
= 0.0197 mol
Therefore, mole fraction will be calculated as follows.
Mol fraction of Xe =
=
= 0.67
Therefore, the mole fraction of Xe is 0.67.
