(x,y)
y=mx+b
m=slope
b=yintercept
slope=7/10
one point is (1,2) or x=1, then y=2
find b
y=7/10x+b
2=7/10(1)+b
2=7/10+b
minus 7/10 both sides
1 and 3/10=b
13/10=b
y=7/10x+13/10
input values for x and get values for y
one point is (0,13/10)
Answer:
$240
Step-by-step explanation:
I = prt
I = (2,400) (0.04) (2.5)
note: I changed 4% to a decimal and 30 months to 2.5 years
I = 96 (2.5)
I = 240 <-- The interest
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The simple interest accumulated on a principal of $ 2,400.00 at a rate of 4% per year for 2.5 years (30 months) is $240.00.
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* Last time I did interest was in 6th grade and I don't remember much. So I am very sorry if my answer is wrong *
Answer:
i think its x= 0.75
Step-by-step explanation:
substitute:
8x × 5 = 40x
8x × 10 = 80x
8 × 5 = 40
5 × 10 =50
40x + 80x = 40 + 50
add like terms
so it'd be:
120x = 90
now divide 90 by 120 and that would give you the value of x alone which is 0.75
Let x be the 1st odd number, and x+2 the second odd consecutive number:
(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1
x² + 2x = 12x +12 - 1
And x² - 10x - 11=0
Solve this quadratic expression:
x' = [+10 +√(10²- 4.(1)(-11)]/2 and x" = [+10 -√(10²- 4.(1)(-11)]/2
x' = [10 + √144]/2 and x" = [10 - √64]/2
x' = (10+12)/2 and x" = (10-12)/2
x = 11 and x = -1
We have 2 solutions that satisfy the problem:
1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity
These are my notes that you can use
