Question

Graph a line that contains the point (6, -5) and has a slope of -2/3.

Answer 1

We know that the equation of the line is in the form $y=-\frac{2}{3}x+b$. To find b, we can use the fact that (6,-5) lies on the line, meaning that both sides of the equation are equal when x=6 and y=-5.

$-5=-\frac{2}{3}(6)+b\\-5=-4+b\\b=-1$

Hence, the equation of the line is $y=-\frac{2}{3}x-1$, and its graph looks something like follows.