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Reil [10]
2 years ago
10

Write a balanced equation for the half-reaction that occurs in the copper half-cell when the cell operates

Chemistry
1 answer:
max2010maxim [7]2 years ago
8 0

Cu (s) → Cu^{+2} (aq) + 2e is the copper half-cell when the cell operates.

<h3>What is half cell reaction?</h3>

A half-cell reaction is either an oxidation reaction in which electrons are lost, or a reduction reaction where electronic are gained.

The reactions occur in an electrochemical cell in which the electrons are lost at the anode through oxidation and consumed at the cathode where the reduction occurs.

Cu (s) → Cu^{+2} (aq) + 2e is the copper half-cell when the cell operates.

Learn more about the half-cell reaction here:

brainly.com/question/11308727

#SPJ1

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Explanation: Please see attachment for explanation.

3 0
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Why is potasium oxide not used to investigate property of hydrogen gas​
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For the following reaction KClO4 → KCl + 2O2 Assign oxidation states to each element on each side of the equation.
Anuta_ua [19.1K]
Oxidation states number (OSN) show how many electrons gained, lost or shared during chemical reactions. 

Here are some rules of oxidation state numbers.

1. OSN of 1A elements in compounds is +1
2. OSN of Oxygen in compounds is -2
3. Sum of OSN of elements equals zero in neutral compounds.
4. OSN of free elements is zero. ex. F2, N2, O2.. all have 0 OSN.

If an element loses electrons during reaction, it is oxidized. That element is called as reducing agent.

If an element gains electrons during reaction, it is reduced. That element is called as oxidizing agent.

In the given reaction, potassium perchlorate decompose into potassium chlorate and oxygen.

a) KClO4.
K (potassium) is 1A element, OSN +1,
Oxygen in the compound has OSN -2.
Let OSN of Cl be x 
1+ x+(4*-2)=0 (since compound is neutral)
Solve the equation. X is equal to +7. 

b)Potassium perchlorate is the reactant, Potassium chloride and Oxygen are the products.
 Reactants -----> Products

c) Check out change of OSN of elements.
in KCl, OSN number of K is +1, Cl is -1. So Cl+7---->Cl-1. It takes 8 electrons. It was reduced.
in KClO4, OSN number of O is -2, in O2 it becomes O. So O-2---->O. It gives electrons. It was oxidized.
Shortly,
LOSS OF ELECTRONS=OXIDIZED 
GAIN OF ELECTRONS=REDUCED

8 0
4 years ago
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