Answer:
4.43 g Cl₂
Explanation:
To find the mass of Cl₂, you need to (1) convert moles HCl to moles Cl₂ (via the mole-to-mole ratio from equation coefficients) and then (2) convert moles Cl₂ to grams (via the molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units. The final answer should have 3 significant figures like the given value.
4 HCl(g) + O₂(g) -----> 2 Cl₂(g) + 2 H₂O(g)
^ ^
Molar Mass (Cl₂): 2(35.453 g/mol)
Molar Mass (Cl₂): 70.906 g/mol
0.125 moles HCl 2 moles Cl₂ 70.906 g
-------------------------- x ---------------------- x ------------------- = 4.43 g Cl₂
4 moles HCl 1 mole
Answer: 12.0 milliliters of 6.50 M HCl ( aq ) are required to react with 2.55 g Zn.
Explanation:
moles =
moles of zinc =
The balanced chemical equation is :

According to stoichiometry:
1 mole of zinc reacts with = 2 moles of HCl
Thus 0.0390 moles of zinc reacts with =
moles of HCl
To calculate the volume for given molarity, we use the equation:
.....(1)
Molarity of
solution = 6.50 M
Volume of solution = ?
Putting values in equation 1, we get:


Thus 12.0 ml of 6.50 M HCl ( aq ) are required to react with 2.55 g Zn
To answer your question, the answer is number 1. hope this help
The given question is incomplete. The complete question is :
A chemist prepares a solution of barium acetate by measuring out 32 g of barium acetate into a 350 ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in of the chemist's barium acetate solution. Round your answer to significant digits.
Answer: The concentration of barium acetate solution is 0.375 mol/L
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

where,
n = moles of solute
= volume of solution in ml
moles of
= 
Now put all the given values in the formula of molality, we get


Therefore, the concentration of solution is 0.375 mol/L