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Mandarinka [93]
2 years ago
9

A jogger has an average stride length of 140 cm and takes an average of 200 steps per minute. The jogger's average speed would b

e
Physics
1 answer:
andreev551 [17]2 years ago
3 0

From the calculations, the speed of the jogger is calculated as 4.7 m/s.

<h3>What is speed?</h3>

The term speed refers to the ratio of distance covered to time taken. In this case we know that;

steps per minute  = 200 steps per minute.

1 stride length = 140 cm

Distance covered in 200 strides = 200 * 140 = 28000 cm or 280 m

time taken = 1 minute or 60 seconds

Speed of the jogger = 280 m/60 seconds = 4.7 m/s

Learn more about speed:brainly.com/question/7359669

#SPJ1

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A 40.0-$kg$ body is moving in the direction of the positive x axis with a speed of 238 $m/s$ when, owing to an internal explosio
Julli [10]

Answer:

v_3 = 400\ m/s

Explanation:

given,

mass of the body = 40 Kg

speed in x-axis = 238 m/s

mass break into three part

m₁ = 7 kg

v₁ = 356 m/s (along the positive y axis)

m₂ = 4.5 kg

v₂ = 357 m/s(along the negative x axis)

m₃ = 40 - (7 + 4.5) = 28.5 Kg

v₃ = ?

using conservation of momentum

MV = m₁v₁ + m₂v₂ + m₃v₃

(40)(238) \hat{i} = (7)(356) \hat{j} - (4.5)(357) \hat {i} + 28.5 v_3

(9520) \hat{i} = 2492 \hat{j} - 1606.5\hat {i} + 28.5 v_3

11126.5 \hat{i} - 2492 \hat{j} = 28.5 v_3

v_3 =390.40 \hat{i} - 87.44 \hat{j}

v_3 = \sqrt{390.40^2 + 87.44^2}

v_3 = 400\ m/s

4 0
3 years ago
When astronauts travel to the moon, their bodies experience a lower gravitational pull than on Earth. Which type of pull are the
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Read 2 more answers
A car is traveling at a speed of 38.0 m/s on an interstate highway where the speed limit is 75.0 mi/h. Is the driver exceeding t
lidiya [134]

Answer:

Yes, the car driver is exceeding the given limit.

Explanation:

<u>Given:</u>

  • Speed of the car, v = 38.0 m/s.
  • Speed limit of the highway, \rm v_o=75.0\ mi/h.

<h2><u>Converting the speed limit from mi/h to m/s:</u></h2>

We know,

1 mi = 1.60934 km.

1 km = 1000 m.

Therefore, 1 mi = 1.60934 × 1000 m = 1609.34 m.

1 hour = 60 minutes.

1 minute = 60 seconds.

Therefore, 1 hour = 60 × 60 seconds = 3600 seconds.

Using these values,

\rm 1\ \dfrac{mi}{h}=\dfrac{1609.34\ m}{3600\ s}=0.447\ m/s.

Therefore,

\rm v_o = 75.0\ mi/h=75.0\times 0.447=33.52\ m/s.

Clearly,

\rm v_o

which means, the car driver is exceeding the given speed limit.

6 0
3 years ago
The truck in which
sertanlavr [38]

Answer:

m = 4

Explanation:

We have,

You apply a force of  600 N to the branch  which acts as a lever. It means it is input force, IF = 600 N

The rear of the truck  weighs 2,400 N. It means it is output force, OF = 2400 N

The ratio of output force to the input force is equal to the mechanical advantage of the lever arm. It is given by :

m=\dfrac{2400}{600}\\\\m=4

So, the mechanical  gain of the lever arm is 4.

8 0
2 years ago
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