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Mandarinka [93]
2 years ago
9

A jogger has an average stride length of 140 cm and takes an average of 200 steps per minute. The jogger's average speed would b

e
Physics
1 answer:
andreev551 [17]2 years ago
3 0

From the calculations, the speed of the jogger is calculated as 4.7 m/s.

<h3>What is speed?</h3>

The term speed refers to the ratio of distance covered to time taken. In this case we know that;

steps per minute  = 200 steps per minute.

1 stride length = 140 cm

Distance covered in 200 strides = 200 * 140 = 28000 cm or 280 m

time taken = 1 minute or 60 seconds

Speed of the jogger = 280 m/60 seconds = 4.7 m/s

Learn more about speed:brainly.com/question/7359669

#SPJ1

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Answer: 19 s

Explanation:

The relationship between speed, distance  and time is given by:

velocity= distance/time

time= distance/velocity= 323 m/17 m/s= 19 s

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What is force? in Newton's Law​
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How many components can be realized of a vector?​
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<em>two different components</em>

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What happens to the force of attraction between two planets when the masses of both are doubled?
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3 years ago
A racecar driver is driving her car down the drag strip at 120 m/s. What is the shortest distance in which she can brake and sto
DaniilM [7]

Answer:

1034.78 m

Explanation:

The shortest distance is the displacement of the car from initial position to final position.

Displacement of body is given using Newton's equations of motion.

Given:

Initial velocity, u = 120 m/s

Final velocity, v = 0 m/s( As the car stops in its final position)

Coefficient of static friction, \mu=0.71

Acceleration due to gravity, g=9.8\textrm{ } m/s^{2}

Now, when brakes are applied, only friction acts on the body in a direction opposite to that of its motion.

The acceleration of the car when friction acts the stopping force is given as:

a=- \mu g.

The acceleration is negative as it reduces the velocity of the motion and acts in the direction opposite to that of the motion.

Plug in 0.71 for \mu and 9.8 m/s² for g. Solve for a.

So, a=-0.71\times 9.8=-6.958\textrm{ }m/s^{2}.

Now, displacement of the car is given using the following equation of motion:

v^{2}=u^{2} +2aS

Here, S is the displacement of the racing car.

Plug in 120 m/s for u, 0 m/s for v, -6.958 m/s² for a. Solve for S. This gives,

0^{2} =(120)^{2}+2(-6.958)S\\13.916S=14400\\S=\frac{14400}{13.916}=1034.78\textrm{ m}

Therefore, the shortest distance in which she can brake and stop is 1034.78 m.

5 0
4 years ago
Read 2 more answers
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