Explanation:
According to the law of conservation of energy
,
Potential energy = kinetic energy
I = 
![mgh = [\frac{1}{2} \times mv^{2}] + [\frac{1}{2} \times (\frac{mr^{2}}{2}) \frac{v^{2}}{r^{2}}]](https://tex.z-dn.net/?f=mgh%20%3D%20%5B%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20mv%5E%7B2%7D%5D%20%2B%20%5B%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20%28%5Cfrac%7Bmr%5E%7B2%7D%7D%7B2%7D%29%20%5Cfrac%7Bv%5E%7B2%7D%7D%7Br%5E%7B2%7D%7D%5D)
mgh = ![[\frac{1}{2} \times mv^{2}] + [\frac{1}{4} \times mv^{2}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20mv%5E%7B2%7D%5D%20%2B%20%5B%5Cfrac%7B1%7D%7B4%7D%20%5Ctimes%20mv%5E%7B2%7D%5D)
v = 7.4 m/s
thus, we can conclude that the translational speed of the cylinder when it leaves the incline is 7.4 m/s.
Answer:
Initial velocity = 10 m/s
θ = 60°
This is the case of projectile motion
So the horizontal component of velocity 10 m/s = 10 cosθ
u = 10 cosθ
u = 10 cos 60°
u=5 m/s
x= 5 m
So in the horizontal direction
x = u .t
5 = 5 .t
t = 1 sec The vertical component of velocity 10 m/s = 10 sinθ
Vo= 10 sinθ
Vo= 10 sin 60°
Vo = 8.66 m/s
h=3.75 m
So height of robot = 3.75 - 0.75 m
height of robot =3 m
The answer is <span>C. 49 m/s
The kinetic equation is:
v2 = v1 + a * t
v1 - initial velocity
v2 - final velocity
a - gravitational acceleration
t - time
We know:
v2 = ?
v1 = 0 (in free fall
a = 9.8 m/s
t = 5
</span>v2 = v1 + a * t
v2 = 0 + 9.8 * 5
v2 = 0 + 49
v2 = 49 m/s
Answer:
Unbalanced forces change the motion of an object. If an object is at rest and an unbalanced force pushes or pulls the object, it will move. Unbalanced forces can also change the speed or direction of an object that is already in motion.
Full moon: All of the moon or sun appears covers by the shadow.
When the moon is waxing, it means that the lit part is getting larger (going towards a full moon)
When the moon is waning , it means that the lit part is getting smaller (going towards a new moon)
The new moon represents the start of a new lunar cycle and occurs approximately every 29 days.
Hope that help:)
