A 17.0-m-high and 11.0-m-long wall and its bracing under construction are shown in the figure. Calculate the force, in newtons,
1 answer:
The force, in newtons, exerted by each of the 10 braces is 2.135 x 10⁴ N.
<h3>What is force?</h3>The force is defined as the shear stress or pressure applied per unit area.
F = P/A
Given is a 17.0-m-high and 11.0-m-long wall and its bracing under construction are shown in the figure(attached). The force is exerted by each of the 10 braces, if a strong wind exerts a horizontal force of 655 N on each square meter of the wall. Assume that the net force from the wind acts at a height halfway up the wall and that all braces exert equal forces parallel to their lengths.
Considering the pivot at the base of wall.
From the equilibrium of forces, we have
r₁ x Fwind = r₁ x Fbsinθ
Put the values, we get
Fb = Fwind /10sin35°.............(1)
The wind force is also given by
Fwind = Horizontal force or pressure x Area
Fwind = F/A x hw
=655 x 17 x 11
F wind = 122,485 N
From equation (1), we have
Fb = Fwind /10sin35°
Fb = 122,485 /10sin35°
Fb = 21,354.6080 N
0r Fb = 2.135 x 10⁴ N
Thus, the force exerted on each of the 10 brace is 2.135 x 10⁴ N.
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Answer:
The question is incomplete. However, I believe, it is asking for the acceleration of the elevator. This is 3.16 m/s².
Explanation:
By Hooke's law,
F is the force on a spring, k is the spring constant and e is the extension or compression.
From the question,
This is the force on the mass suspended on the spring. Its acceleration, a, is given by
This acceleration is more than the acceleration due to gravity, g = 9.8 m/s². Hence the elevator must be moving up with an acceleration of
12.96 - 9.8 m/s² = 3.16 m/s²