Ok, so user says that it should be solve for vertex not vertex form
(x,y)
to find the vertex of
y=ax^2+bx+c
the x value of the vertex is -b/2a
the y value is found by plugging in the x value for the vertex back into the original equation and evaluating
y=-2x^2-12x-28
a=-2
b=-12
xvalue of vertex is -(-12)/(2*-2)=12/-4=-3
x value of vertex is -3
plug backin for x
y=-2x^2-12x-28
y=-2(-3)^2-12(-3)-28
y=-2(9)+36-28
y=-18+8
y=-10
yvalue is -10
x value is -3
vertex is (-3,-10)
X=Elinor´s age today.
y=Mother´s age today.
(x+15)=Elinor´s age after 15 years.
(y+15)=Mohter´s age after 15 years.
We can suggest this systemen of equations:
x/y=3/8 ⇒x=3y/8
(x+15)/(y+15)=6/11 ⇒11(x+15)=6(y+15)
Finally, we´ll have the following system:
x=3y/8
11(x+15)=6(y+15)
We can solve this system of equations by substitution method:
11[(3y/8)+15)=6(y+15)
11[(3y+120)/8)=6y+90
33y+1320=8(6y+90)
33y+1320=48y+720
33y-48y=720-1320
-15y=-600
y=-600/-15
y=40
We find out the value of "x";
x=3y/8
x=3(40)/8
x=120/8
x=15
Answer: Elinor is 15 years old.
The cost of the new lacrosse stick is $13.20
10/18 or 5/9 in simplest form.
