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3 years ago

What is the difference in concentration between a pH of 7 and 12?

Chemistry

2 answers:

Ratling [72]3 years ago

4 0

Answer:

The pH of a solution is simply a measure of the concentration of hydrogen ions,

, which you'll often see referred to as hydronium cations,

More specifically, the pH of the solution is calculated using the negative log base

of the concentration of the hydronium cations.

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

−

log

(

[

]

)

∣

−−−−−−−−−−−−−−−−−−−−−−−−

Now, we use the negative log base

because the concentration of hydronium cations is usually significantly smaller than

As you know, every increase in the value of a log function corresponds to one order of magnitude.

Explanation:

frosja888 [35]3 years ago

3 0

Answer:

ph level of 12 is very high almost bleach but ph level of 7 is about normal.

Explanation:

You might be interested in

a thermometer containing 8.3g of mercury has broken. if mercury ha a density of 13.6g/mL. what volume is spilled?

scoray [572]

D = m / V

13.6 = 8.3 / V

V = 8.3 / 13.6

V = 0.610 mL

hope this helps!

4 0

3 years ago

Read 2 more answers

What is the mass percent of potassium sulfate in solution if 78g of potassium sulfate is dissolved in 500 mL of water? (The dens

Debora [2.8K]

Answer:

13.5 %

Explanation:

First we calculate the mass of 500 mL of water, using its density:

Volume * Density = Mass

500 mL * 1.00 g/mL = 500 g

Then we calculate the mass percent of potassium sulfate, using the formula:

Mass of Potassium Sulfate / Total Mass * 100%

78 g / (78 + 500) g * 100 % = 13.5 %

6 0

2 years ago

A 15.00 % by mass solution of lactose (C 12H 22O 11, 342.30 g/mol) in water has a density of 1.0602 g/mL at 20°C. What is the mo

Alik [6]

Answer:

22.82M

Explanation:

342.3g/mol is présent in 1000

what about in 15??

( 342.3g/mol × 1000 ) ÷ 15

3 0

2 years ago

C15H28 is the formula of

Olegator [25]

Cyclopentadecene is it

5 0

3 years ago

16. The concentration of a solution of potassium hydroxide is determined by titration with nitric

____ [38]

Answer:

$M_{base}=0.709M$

Explanation:

Hello,

In this case, since the reaction between potassium hydroxide and nitric acid is:

$KOH+HNO_3\rightarrow KNO_3+H_2O$

We can see a 1:1 mole ratio between the acid and base, therefore, for the titration analysis, we find the following equality at the equivalence point:

$n_{acid}=n_{base}$

That in terms of molarities and volumes is:

$M_{acid}V_{acid}=M_{base}V_{base}$

Thus, solving the molarity of the base (KOH), we obtain:

$M_{base}=\frac{M_{acid}V_{acid}}{V_{base}} =\frac{0.498M*42.7mL}{30.0mL}\\ \\M_{base}=0.709M$

Regards.

3 0

3 years ago