The balanced chemical equation is :
5P₄ + 36OH → 12HPO₃⁻² (aq) + 8PH₃ (acidic)
Here the oxidation number of P changed from 0 to -3 in PH₃ and increases from 0 to +3 in HPO₃⁻². When P₄ changes to PH₃ reduction reaction is taking place as there is addition of hydrogen and when P₄ changes to HPO₃⁻² oxidation takes place as there is addition of oxygen.
Thus clearly both reduction and oxidation are taking place.
Thus, we can infer that here P₄ is both oxidizing as well as reducing agent.
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The balance chemical equation is follow,
2 I⁻ + SO₄²⁻ + 4 H⁺ → I₂ + SO₂ + 2 H₂O
According to this reaction, 2 moles of I⁻ reacts with 1 mole of SO₄²⁻ to produce 1 mole of I₂ and 1 mole of SO₂.
Result:
So with the formation of 1 mole of I₂, 1 mole of SO₂ is produced.
It would be the change in pressure that would <span>increase the amount of gas able to be dissolved in a given amount of liquid water. Increasing the pressure of a system would allow more gas to be dissolved into a liquid. Hope this answers the question. Have a nice day.</span>
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