Answer: The molecular formula will be 
Explanation:
Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.
Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.
Empirical weight of
is
Molecular mass of compound is = 132 g
Now we have to calculate the molecular formula.
The molecular formula will be=
B. Fluorine (F) is the right answer
The electron geometry of TeCl6 is octahedral, while the molecular geometry is octahedral, non polar.
Octahedral geometry or six electron pairs is the basic geometry for a molecule containing a central atom with six pairs of electrons, such as TeCl6 or SF6. As we replace bonding pairs with non bonding pairs the molecular geometry changes to square pyramidal to square planar.
Answer:
A. Plants
Explanation:
Plants are producers, which make their own food. Other organisms, such as rodents, birds, and wild cats, are consumers, which receive their energy from plants or other consumers.
When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.
The enthalpy of solution of KOH is -57.6 kJ/mol. We can calculate the heat released by the solution (Qr) of 3.66 g of KOH considering that the molar mass of KOH is 56.11 g/mol.

According to the law of conservation of energy, the sum of the heat released by the solution of KOH (Qr) and the heat absorbed by the solution (Qa) is zero.

150.0 mL of solution with a density of 1.02 g/mL were prepared. The mass (m) of the solution is:

Given the specific heat capacity of the solution (c) is 4.184 J/g・°C, we can calculate the change in the temperature (ΔT) of the solution using the following expression.

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.
Learn more: brainly.com/question/4400908