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mestny [16]
3 years ago
11

Explain how a light ray behaves when it strikes a mirror?

Chemistry
2 answers:
Vinvika [58]3 years ago
5 0
The light ray is reflected when it his a mirror.
Trava [24]3 years ago
5 0
The light ray reflects off the mirror.
The direction of the light ray is determined like this:

pretend there is a perpendicular plane to the mirror at where the light strikes the mirror. the light ray is reflected relative to the perpendicular plane, reflecting it across that line/plane. 

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Please help! 30 points!
lisabon 2012 [21]
The person above me is correct
8 0
3 years ago
Suppose 10.0 mL of 2.00 MNaOH is added to (a) 0.780 L of pure water and (b) 0.780 L of a buffer solution that is 0.682 Min butan
katrin2010 [14]

Answer:

a) pH will be 12.398

b) pH will be 4.82.

Explanation:

a) The moles of NaOH added = molarity X volume (L) = 2 X 0.01 = 0.02 moles

The total volume after addition of pure water = 0.780+0.01 = 0.79 L

The new concentration of /NaOH will be:

molarity=\frac{molesofsolute}{volumeofsolution}=\frac{0.02}{0.79}=0.025M

the [OH⁻] = 0.025

pOH = -log [OH⁻] = 1.602

pH = 14 -pOH = 12.398

b) The buffer has butanoic acid and butanoate ion.

i) Before addition of NaOH the pH will be calculated using Henderson Hassalbalch's equation:

pH=pKa+log\frac{[salt]}{[acid]}

pKa=-logKa=-log(1.5X10^{-5})=4.82

ii) on addition of base the pH will increase.

8 0
4 years ago
A balance is used to measure mass
FrozenT [24]

if this is true or false its true hope i helped

6 0
3 years ago
Consider the reaction I2O5(g) 5 CO(g) -------> 5 CO2(g) I2(g) a) 80.0 grams of iodine(V) oxide, I2O5, reacts with 28.0 grams
Allisa [31]

Answer:

Maximum mass of I_2 produces=50.8g;

Explanation:

Firstly balance the chemical reaction,

I_2 O_5+5CO=5CO_2+I_2

Molecular weight of I_2 O_5=334g/mole;  

Molecular weight of CO =28g/mole;

Number of mole of I_2 O_5 given=80g/(334g/mole)=0.239mole;

Number of mole of CO given=28g/(28g/mole)=1 mole  

Moles are:

Number of mole of I_2 O_5=0.239

Number of mole of CO=1;

From the balanced equation,

1 mole of I_2 O_5 reacts with 5 moles of CO;

Hence;

0.239 mole of I_2 O_5  will react with 5*0.239 moles of CO means

Moles of CO that reacts with I_2 O_5  =1.2 mole but we have given 1 mole therefore

I_2 O_5 Will be excess reagent and CO will be the limitting reagent  

And mass of product depends on limiting reagent i.e. mass of CO.

5 mole of CO produces 1 moleI_2 of I_2;

1 mole of CO  produces 1/5 mole of I_2;

Maximum mass of I_2  produces=mole*molecular weight;

Molecular weight of I_2=254g/mole;

Maximum mass of   produces I_2= (1/5)*254=50.8g;

Maximum mass of I_2 produces=50.8g;

3 0
3 years ago
Name one way you benefit from each of the following states of matter
ira [324]
There are so many different answers to this, so I don't know if you're looking for specifics but this is my personal answer.

Liquid- for drinking

Gases- you inhale gases

Solid- they support your weight, such as chairs
6 0
3 years ago
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