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2 years ago

3.

Chemistry

1 answer:

LenKa [72]2 years ago

4 0

Answer: 23 g

the mol of Fe is 11,5/56 = 23/112 (mol)

the mol of CO is $\frac{2,63.10^{24} }{6.10^{23} }= \frac{263}{60}$ (mol)

we have:

Fe2O3 + 3CO => 2Fe + 3CO2

23/112 69/112 23/56

=> the mol of Fe is 23/56 mol

=> the mass of Fe is 23/56.56 = 23 (g)

Explanation:

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Define: 1. acids, 2. strong acids, 3. weak acids.

Reika [66]

H^+ = acid
OH^- = alkaline

Acids have a pH of below 7. The lower the number, the strongest the acid.

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3 years ago

Read 2 more answers

The bomb calorimeter in Exercise 102 is filled with 987g water. The initial temperature of the calorimeter contents is 23.32. A

Sholpan [36]

Answer:

25.907°C

Explanation:

In Exercise 102, heat capacity of bomb calorimeter is 6.660 kJ/°C

The heat of combustion of benzoic acid is equivalent to the total heat energy released to the bomb calorimeter and water in the calorimeter.

Thus:

$-q_{combust} = q_{water} + q_{calori}$

$q_{combust}$ = heat of combustion of benzoic acid

$q_{water}$ = heat energy released to water

$q_{calori}$ = heat energy released to the calorimeter

Therefore,

$-m_{combust}*H_{combust} = [m_{water}*c_{water} + C_{calori}]*(T_{f} - T_{i})$

1.056*26.42 = [0.987*4.18 + 6.66]( $T_{f}$ - 23.32)

27.8995 = [4.12566+6.660]( $T_{f}$ - 23.32)

( $T_{f}$ - 23.32) = 27.8995/10.7857 = 2.587

$T_{f}$ = 23.32 + 2.587 = 25.907°C

4 0

3 years ago

Given:

bulgar [2K]

Answer:

The combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy

Explanation:

Given;

CH₄ + 2O₂ → CO₂ + 2H₂O, ΔH = -890 kJ/mol

From the combustion reaction above, it can be observed that;

1 mole of methane (CH₄) released 890 kilojoules of energy.

Now, we convert 59.7 grams of methane to moles

CH₄ = 12 + (1x4) = 16 g/mol

59.7 g of CH₄ $= \frac{59.7}{16} = 3.73125 \ moles$

1 mole of methane (CH₄) released 890 kilojoules of energy

3.73125 moles of methane (CH₄) will release ?

= 3.73125 moles x -890 kJ/mol

= -3320.81 kJ

Therefore, the combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy

5 0

3 years ago

How many atoms of gold are in a pure gold coin weighing 12.0g?

grigory [225]

12.0g x 1 mol / 63.546g = 0.188839581mol

So, for every 1 mole, we have 6.022 x 10^23 of whatever we're measuring. This gives us a conversion factor of (1 mole / 6.022 x 10^23 atoms) or (6.022 x 10^23 atoms / 1 mole).

0.188839581 mol x (6.022 x 10^23 atoms) / 1 mol = 1.137191955 x 10^23

Remember from before that we are limited to 3 significant figures. Since our calculations are complete, we can now round down to: 1.14 x 10^23 

That should be your answer!

Hope it helps!
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3 years ago

On a coordinate plane, which single transformation could map point A (3,-4) onto point A' (1.5,-2)? *

Ksenya-84 [330]

Answer: A dilation with rule: $(x,y)\to(\dfrac12x,\dfrac12y)$