Question

3.

Answer 1

Answer: 23 g

the mol of Fe is 11,5/56 = 23/112 (mol)

the mol of CO is $\frac{2,63.10^{24} }{6.10^{23} }= \frac{263}{60}$ (mol)

we have:

Fe2O3 + 3CO => 2Fe + 3CO2

23/112    69/112     23/56

=> the mol of Fe is 23/56 mol

=> the mass of Fe is 23/56.56 = 23 (g)

Explanation: