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2 years ago

What was the weakness of the rutherford model of the atom that bohr addressed?

Chemistry

1 answer:

Charra [1.4K]2 years ago

5 0

The weakness of the rutherford model of the atom that bohr addressed is that

The energy of the atom is quantized and
The atom does not lose energy as the electon rotates about the nucleus

<h3>What is Rutherford model of the atom?</h3>

The Rutherford model of the atom proposed by Ernest Rutherford in 1911 shows that the atom is much hollow space with its mass concentrated at the center being surrounded by electrons. It is the planetary model.

<h3>What is the Bohr model of the atom?</h3>

The Bohr model of the atom proposed by Neils Bohr in 1913 suggests that

the energy of an atom is quantized and
that it does not lose energy as the electron rotates about the nucleus.

<h3>What was the weakness of the rutherford model of the atom that bohr addressed?</h3>

The weakness of the rutherford model of the atom that bohr addressed is that

The energy of the atom is quantized and
The atom does not lose energy as the electon rotates about the nucleus

Learn more about Rutherford model of the atom here:

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You might be interested in

What are the controlled variables for water of crystallization experiment?

yarga [219]

Given what we know, we can confirm that as with any experiment, the control variable will be the one that through each trial of the experiment, no matter how many times it is performed, stays constant.

<h3>What is a controlled variable?</h3>

A variable that remains constant through an experiment.
They are used to compare results to the normal condition.
They are also used to isolate the changes to one factor at a time and thus know its exact effects on the outcome.
This increases the accuracy of the data and the subsequent conclusion.

Therefore, we can confirm that if a variable stays constant through each phase and trial of an experiment, it is considered to be a controlled variable and is useful in order to increase the accuracy of the conclusion.

To learn more about control variables visit:

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7 0

3 years ago

What factors do you think should be considered in selecting a metal to use to reclaim copper? Which factor do you think is the m

Lana71 [14]

Answer:

Aluminum

Explanation:

<h3> <em>Aluminum would be the best choice to reuse copper from the copper chloride solution because it In the aluminum–copper reaction, the chloride ions help remove the aluminum oxide coating so that a reaction can take place through the oxidation of aluminum and the reduction of copper ions.The aluminum–copper chloride reaction is a simplified version of a waste reclamation and reduction strategy for handling toxic-waste materials. </em></h3>

7 0

3 years ago

A piece of high-density Styrofoam measuring 24.0 cm by 36.0 cm by 5.0 cm floats when placed in a tub of water. When a 1.5 kg boo

zheka24 [161]

Explanation:

The given data is as follows.

Width of Styrofoam = 24.0 cm

Length of Styrofoam = 36.0 cm

Height of Styrofoam = 5.0 cm

Therefore, volume of the Styrofoam will be calculated as follows.

Volume = length × width × height

= (36.0 × 24.0 × 5.0) $cm^{3}$

= 4320 $cm^{3}$

or, = $4.32 \times 10^{3} cm^{3}$

As Styrofoam partially sinks at 3.0 cm and total height of Styrofoam is 5.0 cm. Hence, height of Styrofoam above the water is (5.0 - 3 cm) = 2 cm.

So, volume of water displaced is as follows.

24.0 cm × 36.0 cm × 2.0 cm

= $1.73 \times 10^{3} cm^{3}$

Hence, mass of displaced water is as follows.

mass = density × volume

= $1.00 g/cm^{3} \times 1.73 \times 10^{3} cm^{3}$

= $1.73 \times 10^{3} g$

Since, book is placed on the Styrofoam. Therefore, mass of water displaced is also equal to the following.

Mass of water displaced = mass of book + mass of Styrofoam

$1.73 \times 10^{3} g$ = 1500 g + mass of Styrofoam

(1730 - 1500) g = mass of Styrofoam

mass of Styrofoam = 230 g

Therefore, calculate the density of Styrofoam as follows.

Density = $\frac{mass}{volume}$

= $\frac{230}{4.32 \times 10^{3} cm^{3}}$

= $53.24 \times 10^{-3} g cm^{-3}$

Thus, we can conclude that the density of Styrofoam is $53.24 \times 10^{-3} g cm^{-3}$ .

4 0

3 years ago

For the reaction: 3 H2(g) + N2(g) <--> 2 NH3(g), the concentrations at equilbrium were [H2] = 0.10 M, [N2] = 0.10 M, and [

masya89 [10]

The equilibrium constant, k of the reaction in which case, the concentrations of the given reactants and products are as indicated is; Choice A; K = 3.1 x 10⁵

<h3>What is the equilibrium constant , k of the reaction as described in the task content?</h3>

It follows from above that the concentrations of the reactants and products are as follows; [H2] = 0.10 M, [N2] = 0.10 M, and [NH3] = 5.6 M at equilibrium.

Hence, the equilibrium constant of the reaction in discuss is;

K = [5.6]²/[0.10]³[0.10]

k = 5.6² × 10⁴

k = 3.136 × 10⁵

K = 3.1 × 10⁵.