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Bess [88]
2 years ago
7

What was the weakness of the rutherford model of the atom that bohr addressed?

Chemistry
1 answer:
Charra [1.4K]2 years ago
5 0

The weakness of the rutherford model of the atom that bohr addressed is that

  • The energy of the atom is quantized and
  • The atom does not lose energy as the electon rotates about the nucleus

<h3>What is Rutherford model of the atom?</h3>

The Rutherford model of the atom proposed by Ernest Rutherford in 1911 shows that the atom is much hollow space with its mass concentrated at the center being surrounded by electrons. It is the planetary model.

<h3>What is the Bohr model of the atom?</h3>

The Bohr model of the atom proposed by Neils Bohr in 1913 suggests that

  • the energy of an atom is quantized and
  • that it does not lose energy as the electron rotates about the nucleus.

<h3>What was the weakness of the rutherford model of the atom that bohr addressed?</h3>

The weakness of the rutherford model of the atom that bohr addressed is that

  • The energy of the atom is quantized and
  • The atom does not lose energy as the electon rotates about the nucleus

Learn more about Rutherford model of the atom here:

brainly.com/question/10866484

#SPJ12

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Answer:

Incomplete combustion of fuels produces a very poisonous gas called carbon monoxide:Excessive inhaling of carbon dioxide gas can kill a person.

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How many milliseconds (ms) are there in 3.5 seconds (s)?
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13 hundred

Explanation:

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Which example is a renewable energy source?
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Based on the sign of E cell, classify these reactions as spontaneous or non spontaneous as written.? assume standard conditions.
sammy [17]
A electrochemical reaction is said to be spontaneous, if E^{0} cell is positive. 

Answer 1:
Consider reaction: <span>Ni^2+ (aq) + S^2- (aq) ----> + Ni (s) + S (s) 

The cell representation of above reaction is given by;
    </span>S^{2-}/S //  Ni^{2+}/Ni

Hence, E^{0}cell =  E^{0} Ni^{2+/Ni} -  E^{0} S/S^{2-}
we know that, {E^{0} Ni^{2+}/Ni  = -0.25 v
and {E^{0} S/ S^{2-}  = -0.47 v

Therefore, E^{0} cell = - 0.25 - (-0.47) = 0.22 v

Since,  E^{0} cell is positive, hence cell reaction is spontaneous
.....................................................................................................................

Answer 2: 
Consider reaction: <span>Pb^2+ (aq) +H2 (g) ----> Pb (s) +2H^+ (aq)
</span>
The cell representation of above reaction is given by;
    H_{2} /  H^{+} //  Pb^{2+} /Pb

Hence, E^{0}cell = E^{0} Pb/Pb^{2+} - E^{0} H_{2}/H^{+}
we know that, {E^{0} Pb^{2+}/Pb = -0.126 v
and {E^{0} H_{2}/ H^{+} = -0 v

Therefore, E^{0} cell = - 0.126 - 0 = -0.126 v

Since,  E^{0} cell is negative, hence cell reaction is non-spontaneous.

....................................................................................................................

Answer 3: 
Consider reaction: <span>2Ag^+ (aq) + Cr(s) ---> 2 Ag (s) +Cr^2+ (aq)
</span>
The cell representation of above reaction is given by;
    Cr/Cr^{2+} // Ag^{+}/Ag

Hence, E^{0}cell = E^{0} Ag^{+}/Ag - E^{0} Cr/Cr^{2+}
we know that, {E^{0} Ag^{+}/Ag = -0.22 v
and {E^{0} Cr/ Cr^{2+} = -0.913 v

Therefore, E^{0} cell = - 0.22 - (-0.913) = 0.693 v

Since,  E^{0} cell is positive, hence cell reaction is spontaneous
8 0
3 years ago
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What is the theoretical yield of SO3 produced by 8.96 g of S?
Virty [35]

Answer: Theoretical yield of SO_3 produced by 8.96 g of S is 33.6 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}

\text{Moles of} S=\frac{8.96g}{32g/mol}=0.28moles

The balanced chemical equation is:  

2S+3O_2\rightarrow 2SO_3  

According to stoichiometry :

2 moles of S produce =  3 moles of SO_3

Thus 0.28 moles of S will produce=\frac{3}{2}\times 0.28=0.42moles  of SO_3  

Mass of SO_3=moles\times {\text {Molar mass}}=0.42moles\times 80g/mol=33.6g

Thus theoretical yield of SO_3 produced by 8.96 g of S is 33.6 g

7 0
2 years ago
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