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Bogdan [553]
2 years ago
12

A 16.42 mL volume of 0.1327 M KMnO4 solution is needed to oxidize 25.00 mL of a FeSO4 solution in acidic medium. What is the con

centration of the FeSO4 solution in molarity?
Chemistry
1 answer:
statuscvo [17]2 years ago
6 0

The concentration of the FeSO4 solution in molarity would be 0.4356

The concentration can be derived first by writing out the balanced equation of the reaction:

  • 5Fe^2^++MnO^4^-+8H^+--->5Fe^3^++Mn^2^++4H_2O

From the balanced equation: for every 1 mole of KMnO4, 5 moles of FeSO4 is needed for complete oxidation.

Recall that: mole = molarity x volume

Mole of KMnO4 needed = 0.1327 x 0.01642

                  = 0.002179 mole

1 mole KMnO4 = 5 mole FeSO4

0.002178 mole = 5 x 0.002178/1

                             = 0.01089 moles of FeSO4

Molarity of FeSO4 = mole/volume

                                 = 0.01089/0.025

                               = 0.4356 M

More on the calculation of molarity of solutions can be found here: brainly.com/question/16587536

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Answer:

Take a look at the attachment below

Explanation:

Take a look at the periodic table. As you can see, Rubidium is the closest element to Cesium, and happens to have the closest boiling point to Cesium, with only a difference of about 30 degrees.

Respectively, you would think that fluorine should have the least similarity to Cesium with respect to it's boiling point, considering it is the farthest away from the element out of the 4 given. This is not an actual rule, there are no fixed trends of boiling points in the periodic table, there are some but overall the trends vary. However in this case fluorine does have the least similarity to Cesium with respect to it's boiling point, a difference of about 1,546.6 degrees.

<em>Hope that helps!</em>

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