The correct answer of equilibrium concentration of BrCl is 0.2292 M.
The balanced chemical equation:
Br2(g) + Cl2(g) = 2BrCl(g)
[Br2] = [Cl2] = (0.2 - x) M
[BrCl] = (2x) M
7.20 = [2x / (0.2 - x)]2
2.6833 = 2x / (0.2-x)
2.6833 × (0.2 - x) = 2x
0.53666 - 2.6833x = 2x
0.53666 = 4.6833x
x = 0.1146
[Br2] = [Cl2] = 0.2 - x = 0.2 - 0.1146 = 0.0854 M
[BrCl] = 2x = (2 × 0.1146) = 0.2292 M
[BrCl] = 0.2292 M
<h3>
What is equilibrium concentration?</h3>
A chemical reaction is considered to be in a state of chemical equilibrium when both the reactants and the products are in a concentration that does not change over time any more. The forward response rate and the backward reaction rate are equal in this condition. You can determine the equilibrium concentration for a reaction if you know the starting concentrations of the constituent chemicals.
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Answer:
Take in carbon dioxide, reduces water loss, and produce oxygen.
Explanation: Hi! I've learned about these things in the past, really tough stuff! Hopefully this helps, I believe the three options above are correct, only one I'm possibly questioning is producing oxygen. Good luck!
Answer: In an experiment, mice were fed glucose (C6H12O6) containing a small amount of radioactive carbon. The mice were closely monitored, and in a few minutes, radioactive carbon atoms showed up in _Carbon dioxide/Carbon IV oxide (CO2)_
Explanation: The end product of Glucose at the end of metabolism is Carbon dioxide, water and ATP.
C6H12O6 + 6O2 ----------> 6CO2 + 6H2O + ATP (Energy)
The carbon is converted to Carbon dioxide. So, the radioactive Carbon appears in the Carbon dioxide/Carbon IV oxide (CO2).
Answer:
106.95 lb of CO2
Explanation:
Equation of reaction:
2C8H18 + 25O2 = 8CO2 + 18H2O
Mass of C8H18 = density × volume = 0.692×12×3.785×1000 = 31430.64 g
From the equation of reaction above,
2 moles of C8H18 (228 g) produced 8 moles of CO2 (352 g)
31430.64 g of C8H18 will produce 31430.6×352/228 = 48524.50 g of CO2 = 48524.50/1000 = 48.52450 kg of CO2 = 48.52450×2.204 = 106.95 lb of CO2
Answer:
20.5 × 10²³ molecules of He
Explanation:
Given data:
Number of moles of He = 3.40 mol
Number of molecules of He = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
18 g of water = 1 mole = 6.022 × 10²³ molecules of water
1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen
For 3.40 moles of He:
3.40 mol × 6.022 × 10²³ molecules
20.5 × 10²³ molecules of He