It has mass and takes up space is correct.
The metal compound in period 3 is a group 1 metal - Na.
the compound is Na2O, the base annyhdride of NaOH :)
Δt = i Kf m
2.86 °C = (1) (1.86 °C kg mol-1) (x / 0.750 kg)
2.86 °C = (2.48 °C mol-1) (x)
x = 1.1532 mol
33.7 g / 1.1532 mol = 29.2 g/mol
Step one write the chemical equation for reaction
= Ag2O + 2(C10H10N4SO2)---> 2 ( AgC10H9N4SO2)
The reacting ratio of Ag2O to AgC10H9N4SO2 is 1:2 from the reaction above
step 2; find the number of moles of AgC10H9N4SO2
that is mass/molar mass
The molar mass of AgC10H9N4SO2 = 107.86 +(12 x10) + (1 x 9) + (4 x 14) +32 +(16 x2) =356.86g/mol
moles is therefore= 25g/356.86g/mol= 0.07moles
by use of mole ratio the moles of Ag2O= 0.0702=0.035moles
mass = moles x molar mass
the molar mass of Ag2O=231.72 g/mol
mass is therefore= 231.72g/mol x 0.035moles= 8.11grams