Answer:
The dimension of mass can be represented as:
Explanation:
We have Force = Mass X Acceleration
= Mass X
or, Mass = Force x
So, dimensions of mass =
=
Answer:
7213.7kg/m³
Explanation:
Given parameters:
Volume of the metal chunk = 0.131m³
Mass of the metal chunk = 945kg
Unknown:
Density of the metal chunk = ?
Solution :
To solve this problem, density is the mass per unit volume. It is mathematically expressed as;
Density =
So;
Density = = 7213.7kg/m³
The calculated weight in newtons is 10 N.
Listed below is the data we will use:
Area A is where the pressure is P. Here are the details we were given:
A=1 cm2, P=101325 N/m, and w=?
Do the area conversion to square meters.
A=1cm2×1m2/1002cm2\s=1×10−4m2
From the definition of pressure, calculate the weight of the air column. In this instance, the air column's weight is determined by multiplying the atmospheric pressure by the air column's base area.
Fw = P atm A
= (101325N/m2) (1 10 4m2)
= 10N
The complete question is - Imagine a square column of the atmosphere, 1 cm on a side, that extends all the way to the top of the atmosphere. How much does this column of air weigh in newtons?
Learn more about Pressure here-
brainly.com/question/8648295
#SPJ4
Answer:
Explanation:
Magnetic moment of one turn of current carrying coil = current x area of coil
= 4.4 x π x 1.05² x 10⁻⁴ Am²
magnetic moment of 340 turns
M = 340 x 4.4 x π x 1.05² x 10⁻⁴
= .5179 Am²
This will act as short bar magnet . Magnetic field due to a short bar magnet at a point on its axis is given by following formula
B = 2 k M / d³ , k is a constant
Putting the given value of magnetic field we can find d.
7.4 x 10⁻⁶ = 2 x 4π x 10⁻⁷ x .5179 / d³
d³ = 2 x 4π x 10⁻⁷ x .5179 / 7.4 x 10⁻⁶
= .1758 m
d = .56 m
= 56 cm