Answer:
0.83m/s
Explanation:
Given parameters:
distance = 1000m
time taken = 20min
Unknown:
Speed of the walking person = ?
Solution:
To solve this problem;
Speed = 
Time taken should be in seconds;
1 min = 60s
20min = 20 x 60 = 1200s
Speed = 
= 0.83m/s
Answer:
The fundamental frequency and length of the pipe are 100 Hz and 1.7 m.
Explanation:
Given that,
Frequency f = 550 Hz
Frequency f' = 650 Hz
We know that,
AMT pipe is open pipe.
(b). We need to calculate the length of the pipe
Using formula of organ pipe
For 550 Hz,
...(I)
For 650 Hz,
...(II)
From equation (I) and (II)
(a). We need to calculate the fundamental frequency for n = 1
Using formula of fundamental frequency
put the value of L
Hence, The fundamental frequency and length of the pipe are 100 Hz and 1.7 m.
We have here what is known as parallel combination of resistors.
Using the relation:
And then we can turn take the inverse to get the effective resistance.
Where r is the magnitude of the resistance offered by each resistor.
In this case we have,
(every term has an mho in the end)
To ger effective resistance take the inverse:
we get,
The potential difference is of 9V.
So the current flowing using ohm's law,
V = IR
will be, 0.0139 Amperes.
Answer:before throwing and after catching the ball
Explanation:
When basketball is in the hand of player net force on it zero as holding force is canceled by gravity Force. During its entire motion gravitational force is acting on the ball which is acting downward. Even at highest point gravity is constantly acting downwards.
After catching the ball net force on it zero as holding force is canceled by gravity force and ball is continue to be in stationary motion.
Answer:
The answer is 1020 meters.
Explanation:
The values given by the problem are:
1. T= The falling time of the rock [Seconds]
2. H=The sound velocity constant [meter/second]
The Velocity normal formula is
V=H/T
340=H/3
340*3=H
This solution considers the physic of the traveling wave sound but not really the rock falling problem, because the problem ask for the height of the cliff not even more.
