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White raven [17]
3 years ago
14

10dm/s=...m/phút=......km/h

Physics
1 answer:
Lynna [10]3 years ago
8 0
150kmp miles to the second power add all together them together then you get 46 to the 3rd ad 104
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A frog leaping upward off his lily pad instead of continuing on in a straight line . Which law is it ?
Romashka [77]

Answer:

I think it's Law of Motion.

Explanation:

Hope my answer has helped you!

7 0
3 years ago
Read 2 more answers
A skydiver free falls from rest. How long does it take for the skydiver to reach 7 m/s?
aev [14]

Answer:

<em>The skydiver needs 0.71 seconds to reach 7 m/s</em>

Explanation:

<u>Free Fall Motion </u>

When an object is dropped in free air (no friction) from a certain height h, it follows a free-fall motion, whose acceleration is due exclusively to gravity. The speed at a moment t when the object is dropped (from rest) is:

V_f=gt

We need to find How long does the skydiver needs to reach 7 m/s. We solve for t

\displaystyle t=\frac{V_f}{g}

\displaystyle t=\frac{7}{9.8}

t=0.71\ sec

The skydiver needs 0.71 seconds to reach 7 m/s

5 0
3 years ago
What type of reaction feels cold to the touch?
IRISSAK [1]

Answer:

Explanation:

An endothermic reaction absorbs heat, so it will be cold to touch.

8 0
3 years ago
Type the correct answer in the box. Round your answer to the nearest tenth. Dina has a mass of 50 kilograms and is waiting at th
katen-ka-za [31]
I guess once you input the numbers into the correct places into the equation it would look like this :
PE = 50 * 9.8 * 5.0
PE = 2,450
6 0
3 years ago
Read 2 more answers
A solid cylinder is released from the top of an inclined plane of height 0.50 m. From what height, in meters, on the incline sho
dangina [55]

Answer:

Explanation:

for rolling motion down the plane acceleration is given by the following expression

a = g sinθ / (1 + k² / R²)

here k is radius of gyration and R is radius of the object rolling down .

for cylinder I = 1/2 m R²

so k² = R² / 2

k² / R² = 1/2

a = g sinθ /( 1 + 1 / 2 )

= 2 / 3 x  g sinθ

v = √ 2 a s

= √ (2 x  2 / 3 x  g sinθ s )

= √ (4  / 3 x  g h  )

= √ (4  / 3 x  g x .5  )

= √ 2g / 3

for sphere  I = 2/5  m R²

so k² = 2/5 R²

k² / R² = 2 / 5  

a = g sinθ / (1 + 2 / 5)  

= 5 / 7  x  g sinθ

v = √ 2 a s

= √ (2 x  5 / 7  x  g sinθ s )

= √ (10/7  x  g h  )

Given

√ (10/7  x  g h  ) = √ 2g / 3

10/7  x  g h  = 2g / 3

h = 14 / 30 m

= .47 m .

5 0
3 years ago
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