Answer:
The scientist will be looking for the velocity of the wave in air which is equivalent to 10^7m/s
Explanation:
If an object in space is giving off a frequency of 10^13Hz and wavelength of 10^-6m then the scientist will be looking for the velocity of the object in air.
The relationship between the frequency (f) of a wave, the wavelength (¶) and the velocity of the wave in air(v) is expressed as;
v = f¶
Given f = 10^13Hz and ¶ = 10^-6m,
v = 10¹³ × 10^-6
v = 10^7 m/s
The value of the velocity of the object in space that the scientist will be looking for is 10^7m/s
<span>It's continuous except for a pair of dark lines.
They are very close together in the yellow/orange section of the spectrum.</span>
Period is 1/frequency
1/425 = 2.353ms
Answer:
First, as you may know, the light travels at a given velocity.
In vaccum, this velocity is c = 3x10^8 m/s.
And we know that:
distance = velocity*time
Now, if some object (like a star ) is really far away, the light that comes from that star may take years to reach the Earth.
This means that the images that the astronomers see today, actually happened years and years ago (So the night sky is like a picture of the "past" of the universe)
Also, for example, if an astronomer sees some particular thing, he can apply a model (a "simplification" of some phenomena that is used to simplify it an explain it) and with the model, the scientist can infer the information of the given thing some time before it was seen.
Answer:
The vertical distance that the ski jumper fell is 417.45 m.
Explanation:
Given;
initial horizontal velocity of the jumper, 
= 26 m/s
horizontal distance of the jumper, dx = 240 m
The time of the motion is given by;
dx = Vₓt
t = dx / Vₓ
t = 240 / 26
t = 9.23 s
The vertical distance traveled by the diver is given by;
initial vertical velocity, 
, = 0
Therefore, the vertical distance that the ski jumper fell is 417.45 m.
