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2 years ago

PLEASE I REALLY NEED HELP!!! ITS NOT MULTIPLE CHOICE BTW :'(

Chemistry

1 answer:

Stella [2.4K]2 years ago

6 0

Answer:

660J/kg.°C

Explanation:

Using the fact that

∆E of metal + ∆E of water = 0

∆E of the metal = Q = m*c*(T2-T1)

Where

Q = heat lost or gained = ?

m = mass of metal in kg = 0.076kg

c = specific heat of the metal = ?

T1 = 96°C

T2=31°C

∆E of the water=Q= m*c*(T2-T1)

Where

Q = 0.120*4180*6.5 = 3260J

Therefore

3,260J + Q of the metal =0

3,260J + 0.076*C*(31.0–96.0)=0

3,260J - 4.94c = 0

3,260 = 4.94c

3,260/4.94 = c

660J/kg.°C = specific heat of the metal

hope this helps:)

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Answer:

185.2 g/mol.

Explanation:

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Solute = lauryl alcohol

Given:

Mass of solute = 5 g

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Answer:

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Explanation:

Data

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Process

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