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3 years ago

What's the answer to this question?

Mathematics

2 answers:

Elena-2011 [213]3 years ago

6 0

The answer for this question is C.

DENIUS [597]3 years ago

4 0

Hey,here is the answer to ur question...!
Teri=4 3/4=19/4
Josie=4 7/8=39/8
Katie=4 9/10=49/10
Ramona=4 4/5=24/5
Now , since all the denominators are not not equal we have to ma the denominators common ;
Therefore , 19/4+39/8+49/10+24/5

Now taking L.C.M of all the denominators we have,
190+195+196+192/40
Therefore ,arranging them from the greatest distance from school to the least ,we have ,
1. Katie=196/40
2.Josie=195/40
3. Ramona=192/40
4. Teri=190/40
Therefore , correct option is option(B.)
Hope this helps u.....

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3 years ago

Suppose box A contains 4 red and 5 blue poker chips and box B contains 6 red and 3 blue poker chips. Then a poker chip is chosen

sergejj [24]

Answer:

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Coin chosen from box B is red.

Event B: Blue poker chip transferred.

Probability of choosing a red coin:

7/10 of 4/9(red coin from box A)

6/10 of 5/9(blue coin from box A). So

$P(A) = \frac{7}{10}*\frac{4}{9} + \frac{6}{10}*\frac{5}{9} = \frac{28 + 30}{90} = 0.6444$

Blue chip transferred, red coin chosen:

6/10 of 5/9. So

$P(A \cap B) = \frac{6}{10}*\frac{5}{9} = \frac{30}{90} = 0.3333$

What is the probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3333}{0.6444} = 0.5172$

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

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3 years ago

There are 100 people in a wedding house, including children, men and women, and there are 100 pappadas to give with Sadya Te.

olga nikolaevna [1]

Answer:

Two possible sets of answers.

5 men, 11 women and 42 children, or

10 men, 2 women and 88 children

Selamat Sadhya!

Step-by-step explanation:

M = number of men

W = number of women

100-M-W = number of children

Total number of pappadas

5M+3W+(100-M-W)/2 = 100

Solve for W

W = (100-9M)/5 .......................(1)

Examine equation (1).

In order to have W as a whole number, M must be multiple of 5

Therefore M = 5 or 10

If M = 5, W = (100-45)/5 = 11 and children = 100-5-11 = 84

If M = 10, W = (100-90)/5 = 2 and children = 100-10-2 = 88

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3 years ago