The molarity of the diluted solution is 0.32 M
Considering the question given above, the following data were obtained:
Volume of stock solution (V₁) = 500 mL
Molarity of stock solution (M₁) = 2.1 M
Volume of diluted solution (V₂) = 3.25 L = 3.25 × 1000 = 3250 mL
<h3>Molarity of diluted solution (M₂) =....? </h3>
The molarity of the diluted solution can be obtained as follow:
<h3>M₁V₁ = M₂V₂</h3>
2.1 × 500 = M₂ × 3250
1050 = M₂ × 3250
<h3>Divide both side by 3250</h3><h3 />
M₂ = 1050 / 3250
<h3>M₂ = 0.32 M</h3>
Therefore, the molarity of the diluted solution is 0.32 M
Learn more: brainly.com/question/22325751
Answer:
<h2>0.5 moles</h2>
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
We have the final answer as
<h3>0.5 moles</h3>
Hope this helps you
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Answer: measure the mass (48.425g) of KCl
Explanation:
To prepare the solution 0.65M KCl we must measure the mass of KCl that would be dissolved in 1L of the solution. This can be achieved by:
Molar Mass of KCl = 39 + 35.5 = 74.5g/mol
Number of mole (n) = 0.65
Mass conc of KCl = n x molar Mass
Mass conc of KCl = 0.65 x 74.5 = 48.425g
Therefore, to make 0.65M KCl, we must measure 48.425g
