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k0ka [10]
2 years ago
15

Вычислить равновесные концентрации частиц в растворе, содержащем 0,01 моль/л Cu(NO3)2 и 1,0 моль/л NH3.

Chemistry
1 answer:
Wewaii [24]2 years ago
3 0

Answer:

i dOnT SpEaK uR lAnGuAgE

Explanation:

ReEEEeEeEeEeEeEeEeEeeEEEeeeeEEEEeeeeeEEeEEeeeeeEEEEEeeeEee

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What substances is a liquid at room temperature
Vesnalui [34]

Answer:

Only two elements are liquid at standard conditions for temperature and pressure: mercury and bromine. Four more elements have melting points slightly above room temperature: francium, caesium, gallium and rubidium.

Explanation:

6 0
3 years ago
Read 2 more answers
ILL MARK BRAINLIEST :)
DanielleElmas [232]

Explanation:

According to the law of conservation of mass, mass can neither be created nor destroyed but it can simply be transformed from one form to another.

For example, Na^{+} + Cl^{-} \rightarrow NaCl

Mass of Na = 23 g/mol

Mass of Cl = 35.5 g/mol

Sum of mass of reactants = mass of Na + mass of Cl

= 23 + 35.5 g/mol

= 58.5 g/mol

Mass of product formed is as follows.

Mass of NaCl = mass of Na + mass of Cl

= (23 g/mol + 35.5) g/mol

= 58.5 g/mol

As mass reacted is equal to the amount of mass formed. This shows that mass is conserved.

As a result, law of conservation of mass is obeyed.

3 0
3 years ago
In which step of a four-stroke engine cycle does the car release CO2, H2O, and CO?
In-s [12.5K]

Answer:

\boxed{\text{exhaust stroke}}

Explanation:

The four strokes are

  1. Intake: The mixture of air and fuel enters the cylinder.
  2. Compression: The mixture is compressed by a factor of about 11.
  3. Ignition: A spark ignites the fuel, which burns and produces CO₂, CO, and H₂O.
  4. Exhaust: The combustion products are expelled from the cylinder.

\text{The cylinder releases CO$_{2}$, CO, and H$_{2}$O during the }\boxed{\textbf{exhaust stroke}}

7 0
2 years ago
____ 26. what is the weight percentage of nitrogen in urea, cn2h4o
Paraphin [41]
Weight percentage of nitrogen can be calculated using the following rule:
weight percentage of nitrogen = (weight of nitrogen / weight of urea) x 100

From the periodic table:
molecular mass of carbon = 12 grams
molecular mass of nitrogen = 14 grams
molecular mass of hydrogen = 1 grams
molecular mass of oxygen = 16 grams

therefore:
mass of nitrogen in urea = 2(14) = 28 grams
mass of urea = 12 + 2(14) + 4(1) + 16 = 60 grams

Substitute with the masses in the equation to get the percentage:
weight percentage of nitrogen = (28/60) x 100 = 46.667%
7 0
3 years ago
Convert 850 mm Hg to kPa. *
Feliz [49]

Answer:

113.324 KPA

Explanation:

4 0
3 years ago
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