Answer:
The net torque is 0.4962 N m
Explanation:
please look at the solution in the attached Word file
Answer:
along the lead, at right angles to the lead at the middle, and at right angles to the lead at one end.
Assume that the ball rolls to the right.
From the velocity-time graph, the acceleration is
a = (0 - 10 m/s)/(4 - 0 s) = -2.5 m/²
Part (a)
Because the mass of the ball is 25g or 0.025 kg, the force that the road exerts on the ball is
F = (0.025 kg)*(-2.5 m/s²) = -0.0625 N
The force is negative because it acts in opposition to the motion of the ball.
Answer: 0.0625 N to the left.
Part (b)
The direction of the force exerted by the road is to the left because it opposes the motion of the ball to the right.
Part (c)
The unit force is 1 N (Newton), with the dimension (kg-m)/s².
Answer:
d. Increase the velocity of the ride and decrease the radius
Explanation:
The normal force in the amusement park ride is produced by the centripetal force. The formula for this force is given as follows:
Fn = mv²/r
where,
m = mass of the body,
v = velocity of the body
r = radius of the path
Therefore, it is clear from the formula that force has a direct relation with the square of velocity and inverse relation with the radius of path. Hence, the design that will enable the rider to feel the greatest Fn will be:
<u>d. Increase the velocity of the ride and decrease the radius</u>