Since the electrons and neutrino are emitted at rigt angles, the nucleus is emitted at opposite side to right angle. So Pe , Pnue and Pnu are the momentum vectors.
Then Pnu^2 = Pe^2 + Pnue^2 => (9.80 âś• 10-23)^2 + (5.70 âś• 10-23)^2
Pnu^2 = 128.53 x 10^-46
Pnu = 1.13 x 10^-22 kg-m/s
The momentum is in quadrant 3 along positive x axis with angle of direction = 180 + arctan (Pnue/Pe) = 180 + 30 (approx) = 210 degrees
Answer:
solved
Explanation:
a) F_net = (F2 - F3)i - F1 j
b) |Fnet| = sqrt( (F2 - F3)^2 + F1^2)
= sqrt( (9- 5)^2 + 1^2)
= 4.123 N
c) θ = tan^-1( (Fnet_y/Fnet_x)
= tan^-1( -1/(9-5) )
= -14.036°
Answer:
Explanation:
When loading muzzle-loading firearm it is important to eliminate any air space between the projectile and the powder charge because it may create dangerous pressure build inside the muzzle.
The high amount of Pressure build-up may backfire the bullet and may cause harm to the fireman. It creates a high magnitude impulse on the fireman which can be dangerous for his body parts. High pressure may also explode the gun powder on the spot and causes a fire.
Sorry I don’t know the exact answer
Answer:
d = 329.81m
Explanation:
V_f = V_0+a*t
V_f = Velocity final
V_0 = Velocity initial
a = acceleration
t = time
V_f = (0m/s)+(9.81m/s²)*(8.2s)
V_f = 80.442m/s
d = ((V_f-V_0)/2)*t
d = distance
d = ((80.442m/s-0m/s)/2)*(8.2s)
d = 329.81m