Answer:
Explanation:
Since the sound bouncing back from car has greater frequency , the car must be moving towards the police car . If v be the velocity of car
f = 
f is apparent frequency , f₀ is original frequency , V is velocity of sound and v is velocity of car
1270 = 
1.02419 = 
348.22-1.02419v =340 +v
2.02419v = 8.22
v = 4.06 m /s
B)
In this case , we shall take relative velocity in place of velocity of car .So
v = 20+4.06
= 24.06 m /s
f =
= 
1240 x 
= 1428 Hz .
Answer:
The minimum possible coefficient of static friction between the tires and the ground is 0.64.
Explanation:
if the μ is the coefficient of static friction and R is radius of the curve and v is the speed of the car then, one thing we know is that along the curve, the frictional force, f will be equal to the centripedal force, Fc and this relation is :
Fc = f
m×(v^2)/(R) = μ×m×g
(v^2)/(R) = g×μ
μ = (v^2)/(R×g)
= ((25)^2)/((100)×(9.8))
= 0.64
Therefore, the minimum possible coefficient of static friction between the tires and the ground is 0.64.
Answer:
10 kg
Explanation:
The question is most likely asking for the mass of the bicycle.
Momentum is the product of an object's mass and velocity. Mathematically:
p = m * v
Where p = momentum
m = mass
v = velocity
Hence, mass is:
m = p / v
From the question:
p = 25 kgm/s
v = 2.5 m/s
Mass is:
m = 25 / 2.5 = 10 kg
The mass of the bicycle is 10 kg.
In case the question requires the Kinetic energy of the bicycle, it can be gotten by using the formula
K. E = ½ * p * v
K. E. = ½ * 25 * 2.5 = 31.25 J
Answer:
1.931 kilometres is the answer of 1.2 miles
