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IRINA_888 [86]
3 years ago
6

Newton’s first law relates motion to balanced and unbalanced forces.

Physics
2 answers:
BlackZzzverrR [31]3 years ago
8 0
True, an object at rest stays and rest and an object in motion stays in motion
gulaghasi [49]3 years ago
8 0

YES !  

True and certainly.  

Uh huh, uh huh.

That's a fact.  

More intense veracity is seldom encountered.

Did you have a question to ask ?

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If HST has a tangential speed of 7,750 m/s, how long is HST’s orbital period? The radius of Earth is 6.38 × 106 m. s
Sladkaya [172]
 the orbital period is 5170 s
6 0
3 years ago
*Materials that regulate the flow of current through them *
4vir4ik [10]

Answer:

electromagnet

Explanation:

mark me as brainlest

3 0
2 years ago
A water balloon is thrown horizontally from a tower that is 45 m high. It strikes the shoes of an unsuspecting passerby who is 4
LekaFEV [45]

Answer:

14.85 m/s

Explanation:

From the question given above, the following data were obtained:

Height (h) of tower = 45 m

Horizontal distance (s) moved by the balloon = 45 m

Horizontal velocity (u) =?

Next, we shall determine the time taken for the balloon to hit the shoe of the passerby. This is illustrated below:

Height (h) of tower = 45 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

45 = ½ × 9.8 × t²

45 = 4.8 × t²

Divide both side by 4.9

t² = 45/4.9

Take the square root of both side

t = √(45/4.9)

t = 3.03 s

Finally, we shall determine the magnitude of the horizontal velocity of the balloon as shown below:

Horizontal distance (s) moved by the balloon = 45 m

Time (t) = 3.03 s

Horizontal velocity (u) =?

s = ut

45 = u × 3.03

Divide both side by 3.03

u = 45/3.03

u = 14.85 m/s

Thus, the magnitude of the horizontal velocity of the balloon was 14.85 m/s

4 0
3 years ago
Every force has one and only one 3rd law pair force. every force has one and only one 3rd law pair force.
Likurg_2 [28]
I would have to say B failed because I think I read something about it being only 2law not 3
7 0
3 years ago
Read 2 more answers
How much heat is needed to vaporize 10.00 grams of water at 100.0°C? The latent heat of vaporization of water is 2,259 J/g
Nata [24]

Answer:

Heat of vaporization will be 22.59 j    

Explanation:

We have given mass m = 10 gram

And heat of vaporization L = 2.259 J/gram

We have to find the heat required to vaporize 10 gram mass

We know that heat of vaporization is given by Q=mL, here m is mass and L is latent heat of vaporization.

So heat of vaporization Q will be = 10×2.259 = 22.59 J

8 0
3 years ago
Read 2 more answers
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