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ankoles [38]
3 years ago
13

What is the current in a circuit with a 4.5 V battery and a 9 Ω resistor?

Physics
2 answers:
Art [367]3 years ago
7 0
Hi I think is 0.5A I hope it was help full
horsena [70]3 years ago
3 0

Answer:

V=I×R

<em>4</em><em>.</em><em>5</em><em> </em><em>=</em><em> </em><em>I×</em><em>9</em>

<em> </em><em> </em><em> </em><em>I</em><em>.</em><em> </em><em>=</em><em> </em><em>4</em><em>.</em><em>5</em><em>/</em><em>9</em>

<em> </em><em> </em><em> </em><em>I</em><em>. </em><em>=</em><em> </em><em>0</em><em>.</em><em>5</em><em> </em><em>A</em>

<em>curre</em><em>nt</em><em> </em><em>is</em><em> </em><em>0</em><em>.</em><em>5</em><em> </em><em>A</em>

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A potter's wheel has the shape of a solid uniform disk of mass 7 kg and radius 0.65 m. It spins about an axis perpendicular to t
ozzi

Answer:

1.832 kgm^2

Explanation:

mass of potter's wheel, M = 7 kg

radius of wheel, R = 0.65 m

mass of clay, m = 2.1 kg

distance of clay from centre, r = 0.41 m

Moment of inertia = Moment of inertia of disc + moment f inertia of the clay

I = 1/2 MR^2 + mr^2

I = 0.5 x 7 x 0.65 x 0.65 + 2.1 x 0.41 x 0.41

I = 1.47875 + 0.353

I = 1.832 kgm^2

Thus, the moment of inertia is 1.832 kgm^2.

5 0
4 years ago
What is the change in electric potential energy in moving an electron from a location 3 × 10-10 m from a proton to a location 7
joja [24]

Answer:

4.39 x 10^-19 J

Explanation:

q1 = 1.6 x 10^-19 C

q2 = - 1.6 x 10^-19 C

r1 = 3 x 10^-10 m

r2 = 7 x 10^-10 m

The formula for the potential energy is given by

U1 = k q1 q2 / r1 = - (9 x 10^9 x 1.6 x 10^-19 x 1.6 x 10^-19) / (3 x 10^-10)

U1 = - 7.68 x 10^-19 J

U2 = k q1 q2 / r2 = - (9 x 10^9 x 1.6 x 10^-19 x 1.6 x 10^-19) / (7 x 10^-10)

U2 = - 3.29 x 10^-19 J

Change in potential energy is

U2 - U1 = - 3.29 x 10^-19 + 7.68 x 10^-19 = 4.39 x 10^-19 J

5 0
4 years ago
20- A gram of distilled water at 4° C:
Usimov [2.4K]

Answer:

D. will decrease slightly in volume when heated to 6° C

Explanation:

6 0
3 years ago
Which of the following is not a necessary condition for seeing a magnified image with a
Thepotemich [5.8K]

The option stating that the observer must be placed within the focal length is false or not a necessary condition for magnification.

Explanation:

Lens are used for magnification provided the nature of the lens is known and by positioning the object at correct position. So the object should be placed in the focal point of the lens for perfect magnification, it can also be kept within the focal point or focal length. But the object should not be kept beyond the focal length of the lens.

So among the given options, the object and image should be on the same side of the lens for magnification is true. Then the nature of lens should be converging for magnification is also true. And the most important point that the object should be placed within the focal length of the lens is the most mandatory for obtaining magnification. So the option stating that the observer must be placed within the focal length is false or not a necessary condition for magnification.

5 0
3 years ago
If I am plotting a graph to my physics practical result. If they ask me to find the x-intercept, what should I consider when plo
Virty [35]

Answer:

• When getting x-intercept, <u>your vertical axis or y-axis must have it's callibration and demarcation starting from zero.</u>

Explanation:

As well as when getting y-intercept<u>, your horizontal axis or x-axis must have it's callibration and demarcation starting from zero.</u>

<u>.</u>

7 0
3 years ago
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