At 6: 00 am, a motorbike set off from town A to town B at a speed of 40km/h. At the same time, a car set off from town B to town
1 answer:
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Answer:
i) 5 /
ii) 54
iii) 54
Explanation:
i) ⇒
= 5² ÷ 5 = 5
ii) ⇒
= 108 ÷ 10 = 10.8
,
⇒
10.8 × 5 = 54
iii) F1 = F2 = 54
Answer:
12.5 m/s
Explanation:
The motion of the hammer is a free fall motion, so a uniformly accelerated motion, therefore we can use the following suvat equation:
Where, taking downward as positive direction, we have:
s = 8 m is the displacement of the hammer
u = 0 is the initial velocity (it is dropped from rest)
v is the final velocity
is the acceleration of gravity
Solving the equation for v, we find the final velocity:
So, the final speed is 12.5 m/s.