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Alex_Xolod [135]
3 years ago
15

Explain why chlorine forms a -1 ion, but sulfur forms a -2 ion.

Physics
1 answer:
alukav5142 [94]3 years ago
8 0

For a chlorine atom to become a chloride ion, it must gain an electron.The chloride ion has a negative charge and is written as Cl-. Chlorine gains an electron because it has seven valence electrons, and to be a full octet, it gains an electron.

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A cup containing 200 g of hot water is taken off the stove placed on the kitchen table. Initially the water is at 75Degree C. bu
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Answer:

ΔH = -45.1872 kJ , where negative sign signifies heat loss.

Q = ΔH = -45.1872 kJ  , where negative sign signifies heat loss.

S system = -0.141 kJ/K

S surroundings = 0.1536 kJ/K

S universe = -0.141 kJ/K + 0.1536 kJ/K  = 0.0126 kJ/K

Explanation:

Given:

Cp = 4. 184 J/(mole. K)

T₁ = 75 ⁰C

T₂ = 21 ⁰C

Mass of water = 200 g = 0.2 kg

Since,

\Delta H=m\times C\times (T_f-T_i)

ΔH = 0.2*4.184*(21-75)  kJ

<u> ΔH = -45.1872 kJ , where negative sign signifies heat loss.</u>

Since the process is at constant pressure

<u> Q = ΔH = -45.1872 kJ  , where negative sign signifies heat loss.</u>

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

T₁ = 75 ⁰C = 348 .15 K

T₂ = 21 ⁰C = 294.15 K

The entropy of the water is given by:

<u> S = m×Cp×ln(T₂ /T₁) </u>

S = 0.2*4.184*ln(294.15/348.15)

<u> S system = -0.141 kJ/K</u>

The heat gain by surroundings

<u> dQ = -Qreaction =  45.1872 kJ </u>

The entropy change of surroundings is

S surr = dQ/T₂ = 45.1872/294 .15

<u> S surr = 0.1536 kJ/K </u>

The entropy of universe  is the sum total of the entropy of the system and the surroundings and thus,

S universe = Ssys + Ssurr

<u> S universe = -0.141 kJ/K + 0.1536 kJ/K  = 0.0126 kJ/K</u>

4 0
3 years ago
Un cuerpo de 1250 kg se mueve sobre una superficie horizontal por la acción de un mo tor que produce una fuerza de 24500 N. Sabi
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The correct answer is b) 7,9 m/s
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3 years ago
What three sprites are needed to create the Space Invaders game that was discussed in the unit? spaceship, laser, enemy gnome, a
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Answer: anlien, enemy gnome, spaceship

Explanation:

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2 years ago
A rocket is fired in deep space, where gravity is negligible. If the rocket has a mass of 6000 kg and ejects gas at a relative v
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25 miles per second worth of gas

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3 years ago
You serve a tennis ball from a height of 1.80 m above the ground. The ball leaves your racket with a velocity of 18.0 m/s at an
Delicious77 [7]

Answer:

Yes, ball will clear the net

Explanation:

First we have to find the range of projectile motion.

Data given,

Ф = 7°

Initial velocity = 18 m/s

R = (V)^2.sin2Ф/g

Now by putting values

R = 7.99 m

Now for height

h = v^2.(sinФ)^2/2g

by putting values

h = 0.245 m

Since range is less than our distance (11.83 m) from net, so still it is not clear that ball will clear the net or not.

So, now from the maximum height, we have to calculate the horizontal distance of ball to net.

Now velocity in projectile motion is in two dimensions.

V(x) = 18 m/s

V(y) = 0 m/s (because at maximum height, ball will stop and then start again, so y-component of velocity will be 0 but since there will be no acceleration along x-axis, so V(x) will be 18 m/s)

Now, by formula S = V(y)t + (1/2)gt^2

we can calculate time which is required by the ball to reach net from the maximum height it has achieved.

Now, tricky part is to calculate S, because without it we can not calculate t.

So, by data given in question, we know that the ball is served at height of 1.8 m and it achieved the height of 0.245 m. But net is at height of 1.07 m.

So, the vertical distance downward, which ball will travel from maximum height to net will be

S = 1.8 + 0.245 - 1.07

S = 0.975 m

Since we know V(y) = 0 m/s

S = (1/2)gt^2

t = (2S/g)^(1/2)

t = 0.44 s

Now time for both vertical and horizontal distance are same,

So, for horizontal distance "D(x)"

D(x) = V(x) x t (Since, no acceleration along x axis, so we can use simple formula to calculate distance)

D(x) = 18 x 0.44

D(x) = 8.029 m

Now please notice that at maximum height, range was half, so at that point ball covered distance "a"

a = 3.99 m

From maximum height to net, as we calculated, ball covered

D(x) = 8.029 m

So, total distance covered by ball

a + D(x) = 3.99 + 8.029

a + D(x) = 12.024 m

which is more than your total distance from net which is 11.83 m. So, the ball will clear the net.

7 0
3 years ago
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