Write the equation of a function whose parent function, f(x) = x + 8, is shifted 2 units to the right.

Hi, can someone please give me a detailed explanation on how to solve this problem?

Dovator [93]

Answer:

Step-by-step explanation:

log3^(2x+3) = log243

(2x+3)log3 = log243

2x+3 = log243/log3

2x = (log243/log3)-3

x = [(log243/log3)-3]/2

x = (5-3)/2

x = 2/2

x = 1

Check:

3^2(1)+3 = 243

3^2+3 = 243

3^5 = 243

3×3×3×3×3 = 243

9×9×3 = 243

81×3 = 243

243 = 243

5 0

2 years ago

. The asset requires a capital investment of $100 comma 000100,000, and MARR is 1212% per year. Use Monte Carlo simulation an

mylen [45]

Answer:

Hello there, please see step by step explanations to get answer.

Step-by-step explanation:

Given that:

The asset requires a capital investment of $100 comma 000100,000, and MARR is 1212% per year. Use Monte Carlo simulation and generate four trial outcomes to find its expected equivalent AW if each useful life is equally likely to occur.

Please checj attachment fir clarity if answer and solving.

4 0

3 years ago

Helpp, since this question is a bit hard, ill give brainliest and 20 pts.

Morgarella [4.7K]

Step-by-step explanation:

A. When dealing with large numbers, sometimes it's easier to write them in a form of exponents of number ten. The value of the exponent shows how many times we multiply 10 by itself. That means that 10^3 is 10•10•10 or that 10^6 is 10•10•10•10•10•10.

So, when finding how many times on number is greater then the other, we need to divide them. We divide 8x10^6 by 2x10^5. It is done by dividing the numbers and subtracting the exponents; 8/2=4 and 10^6/10^5 is 10^6-5=10^1. So the correct answer is 4x10^1 which is 4x10, and that is 40.

B. Now, we have a total number of coins (2.25x10^5), and diametar of a coin (19mm = 19x10^-6km). Our task is to calculate the distance across which the coiks laid side-by-side would expand. We can find this by multiplying the number of coins with a diametar of single penny, 2.25x10^5•19x10^-6. Multiplying is done by multiplying the numbers (2.25x19=42.75) and adding the exponents (5+(-6)=5-6=-1). So, the distance is 42.75x10^-1km, which equals to 4.275 km. Obviously, this is less then the stated 5 km given in the text, so the reportet's statement is false.

5 0

3 years ago

Jesse is sanding a circular wooden table that has a diameter of 6 ft. She can sand 5 square feet every hour. At this rate, appro

Ilya [14]

The time it will take Jesse to finish sanding the table is approximately 22.61 hours.

<h3>How to find the area of a circle?</h3>

Suppose the circle has radius of 'r' units, then, its area is given as:

$A = \pi \times (r)^2$ sq. units

Since radius of a circle is half of its diameter, so if diameter is of 'd' length, then r= d/2, thus, area can be rewritten as:

$A = \pi \times (\dfrac{d}{2})^2$ sq. units

For the given case, sanding being done needs to be equal to the area of the circular table, as it has to be done for whole table's surface, which is circular, and area of sanding done will be equal to the area of that circular table.

The area of table(diameter given as 6 ft) is: $A = \pi \times (\dfrac{d}{2})^2 \approx 3.14 \times 6^2 = 113.04 \: \rm ft^2$

Since Jesse does 5 sq. feet per hour, let she takes T hours time to finish sanding the table, then we have:

$\rm T \times 5\: ft^2 = A \approx 113.04 \: ft^2\\\\\text{Dividing all sides by 5, we get}\\\\T = \dfrac{113.04}{5} \approx 22.61 \: hours$

(since 5 sq. feet in 1 hours, then in T hours, T times 5 sq. feet will be done which is equal to area of table, as in approx T hours, she finishes sanding the table)

Thus, it will take approx 22.61 hours for Jesse to finish sanding the table.

Learn more about area of circle here:

brainly.com/question/13056790

8 0

2 years ago

Read 2 more answers

How many roots does a quadratic have if the discriminant if prime?

scZoUnD [109]

"The discriminant is prime?" I haven't heard that one before.

Here are the general rules:

1. a positive discriminant results in two real, unequal roots.

2. a zero discr. results in two real, equal roots.