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zhuklara [117]
3 years ago
15

How does a real image differ from a virtual image?

Physics
1 answer:
nikdorinn [45]3 years ago
7 0

Answer:

Real images are obtained using a converging lens or a concave mirror. The size of the real image depends upon the placement of the object. A virtual image is an upright image that is achieved where the rays seem to diverge. A virtual image is produced with the help of a diverging lens or a convex mirror.

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A magnetic field of 0.276 T exists in the region enclosed by a solenoid that has 517 turns and a diameter of 10.5 cm. Within wha
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Answer:

The period the field must be reduced to zero is 9.81 x 10⁻⁵ s

Explanation:

Given;

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The induced emf is given by Faraday's law;

emf = -\frac{NA\Delta B}{t} \\\\emf = -\frac{NA (B_2 -B_1)}{t} \\\\t = -\frac{NA (B_2 -B_1)}{emf}\\\\t = \frac{NA (B_1 -B_2)}{emf}\\\\where;\\\\t \ is \ the \ time \ when \ B = 0 \ \ (i.e\ B_2 = 0)\\\\A \ is \ the \ area \ of \ the \ coil\\\\A = \frac{\pi d^2}{4} = \frac{\pi (0.105)^2}{4} = 0.00866 \ m^2\\\\t= \frac{(517) \times (0.00866)\times  (0.276 -0)}{12,600}\\\\t = 9.81 \times 10^{-5} \ s

Therefore, the period the field must be reduced to zero is 9.81 x 10⁻⁵ s

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