two people, each with a mass of 70 kg, are wearing inline skates and are holding opposite ends of a 15m rope. One person pulls f
1 answer:
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Answer:
The <u>HIGHER</u> value of coefficient of friction the greater the resistance to sliding
Explanation:
As we know that friction force is given by
so friction force is the product of friction coefficient and normal force.
So here we can say that if friction coefficient is higher then the friction force will be more as it is product of friction coefficient and normal force.
So correct answer will be given as
The <u>HIGHER</u> value of coefficient of friction the greater the resistance to sliding
Answer:
force required to push the block = 219.714 lb
Explanation:
GIVEN DATA:
weight W of block = 250 lb
coefficient of friction = 0.2
consider equilibrium condition in x direction
.........................(1)
consider equilibrium condition in Y direction
.....................(2)
SOLVING 1 and 2 equation we get N value
N = 326.36 lb
putting N value in either equation we get force required to push the block = 219.714 lb
